ORIGINAL WORKED EXAMPLE
A substitution system
Solve y=2x+1 and 3x+y=16.
- Replace y in the second equation: 3x+(2x+1)=16.
- 5x=15 gives x=3, then y=7.
- Check 7=2·3+1 and 3·3+7=16.
Answer (x,y)=(3,7)
GRE · Algebra · TOPIC LESSON
Find values that satisfy every condition, and recognize when a system fixes only part of the information.
BY THE END, YOU CAN
BEFORE YOU START
Original educational lesson. Work through the examples before revealing the practice answers. This original lesson supports current GRE General Test study; it does not reproduce official questions, certify a writing score or predict test content.
LEARN THROUGH ORIGINAL PRACTICE
All teaching passages, writing prompts, examples and exercises in this lesson are original. No official ETS questions, prompts or explanations are reproduced. Current structure and observed public sample metadata are separate from this original teaching; no official score or question probability is implied.
01 / UNDERSTAND & APPLY
A system is a collection of conditions that apply simultaneously. A pair (x,y) solving one equation is not enough; it must satisfy every equation and all domain restrictions. Two linear equations in two variables can have one solution, no solutions, or infinitely many.
Choose variables with units, and keep their meanings unchanged. An equation for total objects and another for total cost are independent conditions; writing the same relationship twice in different forms supplies no additional information.
02 / UNDERSTAND & APPLY
Substitution is efficient when one equation already isolates a variable or has coefficient 1 or −1. Solve that equation for a variable, then replace every occurrence of that variable in the other equation. Parenthesize the substituted expression so all signs and factors distribute correctly.
Once one value is found, substitute back for the other, and verify the ordered pair in both originals. The order in (x,y) matters.
ORIGINAL WORKED EXAMPLE
Solve y=2x+1 and 3x+y=16.
Answer (x,y)=(3,7)
03 / UNDERSTAND & APPLY
Adding equations preserves common solutions. Multiply one or both equations by nonzero constants so coefficients of a chosen variable are opposites, then add. Multiply every term, including the right side. Subtraction is equally valid but requires careful handling of the entire second equation.
If the question asks for a sum or difference, an equation combination may produce it directly. Solving for each individual variable can be unnecessary.
ORIGINAL WORKED EXAMPLE
Solve 2x+3y=17 and 5x−2y=14.
Answer (4,3)
04 / UNDERSTAND & APPLY
For nonvertical lines written y=mx+b, different slopes give one intersection. Equal slopes with different intercepts give distinct parallel lines and no solution. Equal slopes and equal intercepts give the same line and infinitely many solutions. Algebraically these cases yield a unique value, a contradiction, or an identity.
A zero coefficient requires care; vertical lines cannot be written with a finite slope. More generally, compare whole equations, including constants. Proportional left-hand coefficients do not guarantee dependent equations if their right-hand constants are not proportional.
ORIGINAL WORKED EXAMPLE
Classify 2x−y=5 and 4x−2y=13.
Answer No solution
05 / UNDERSTAND & APPLY
If every solution satisfies x+y=8, the sum is known even though x and y may vary. A dependent system can therefore determine a requested expression without determining the pair. Conversely, knowing a sum does not fix the product or difference.
For QC, distinguish lack of a unique variable from lack of a unique comparison. Use equation combinations to see what remains fixed, then use two valid solutions to test what varies.
ORIGINAL WORKED EXAMPLE
Suppose 2x+2y=14 and x+y=7. Find 3x+3y.
Answer 21
06 / UNDERSTAND & APPLY
Simultaneous inequalities require their intersection. In one variable, solve each and keep only their common interval. In two variables, each linear inequality describes a half-plane; include its boundary for ≤ or ≥ and exclude it for < or >.
To identify the side of a line, test a point not on the boundary, such as the origin if allowed. A dashed boundary signals exclusion, a solid one inclusion. The overlap of shaded regions contains feasible points; a boundary intersection alone does not establish that a point satisfies all restrictions.
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ORIGINAL WORKED EXAMPLE
Solve 2x−1>5 and 3x+2≤20 simultaneously.
Answer (3,6]
ORIGINAL WORKED EXAMPLE
Describe the solution region of y≥x−1 and y<−x+3, and test (0,0) and (0,4).
Answer x<2 and x−1≤y<−x+3; (0,0) is feasible, (0,4) is not.
07 / UNDERSTAND & APPLY
A standard model uses x+y=N for the count and px+qy=C for a cost, mass or revenue total. Another uses distance=rate×time for each traveler plus a shared distance or time relationship. Units must match across each equation.
Check feasibility after algebra. A ticket count of −2 or a fractional number of indivisible items cannot describe the stated situation. If a system is inconsistent, do not choose the “closest” pair unless the question explicitly permits approximation.
08 / UNDERSTAND & APPLY
All examples and practice in this lesson are original. For quantitative comparison (QC), use A if Quantity A is greater, B if Quantity B is greater, C if they are equal, and D if the relationship cannot be determined from the information given. A, B or C must hold for every permitted case. To establish D, give two allowed cases producing different relationships; an inability to calculate is not itself evidence for D.
A single-answer question requires one choice. For multiple-answer questions, obey the stated selection count or select every correct option if instructed. Test each option separately; do not stop after finding one. Multiple-answer questions receive credit only when the complete correct set is selected, with no incorrect choices. Numeric entry requires the requested value, with units handled in the calculation; round only when the question directs you to. A single numeric-entry box accepts an integer or decimal; a pair of fraction boxes accepts an integer numerator and a nonzero integer denominator. Fractions need not be reduced, but reducing makes checks easier. Do not enter a percent sign when the requested number is a percentage. Preserve exact fractions until the last step.
A calculator can check arithmetic but cannot decide the domain, interpretation or denominator for you. Estimate sign and size first, enter parentheses carefully, and compare the result with the original conditions. Cancel factors or exploit structure when doing so is faster and more reliable than decimal entry.
09 / UNDERSTAND & APPLY
Check answers in all original equations.
ORIGINAL PRACTICE · 1
7
Add equations to obtain 2x=14. The other value is y=4, and both equations check. Reporting 4 would answer for the wrong variable.
ORIGINAL PRACTICE · 2
B
Adding gives 3x=12, hence x=4 and y=1. Other choices may satisfy one equation but fail the other.
ORIGINAL PRACTICE · 3
A, C and E
A has sum 3 and y=2; C has sum 5 and y=5; E has sum 4 and y=6. B has sum 6, too large; D has y=1, too small. Equality on either boundary is permitted.
ORIGINAL PRACTICE · 4
D
Pairs (5,1) and (1,5) satisfy the condition and reverse the comparison. A fixed sum does not order its two parts.
ORIGINAL PRACTICE · 5
5
Subtract the second whole equation from the first to get 2x=10. Substitution gives y=2; every constant must be subtracted as well.
ORIGINAL PRACTICE · 6
A
The slopes match but intercepts differ, so the lines are distinct and parallel. Equal slopes alone do not mean identical lines.
ORIGINAL PRACTICE · 7
8
Let L be large and S small. S+L=20 and 3S+5L=76. Substitute S=20−L: 60+2L=76, so L=8 and S=12.
ORIGINAL PRACTICE · 8
C
Dividing the equation by 2 fixes the requested expression at 5, even though x and y individually are not unique. Indeterminate variables do not automatically imply QC choice D.
KEEP THE BIG IDEAS
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