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GRE · Algebra · TOPIC LESSON

Linear equations and word-problem models

Translate relationships into one consistent variable and preserve equivalence while solving.

GRE General Test40 min study guide9 indexed sections

BY THE END, YOU CAN

  • Solve linear equations including special cases.
  • Build and check cost, age, mixture and rate models.
  • Interpret solutions using domain and units.

BEFORE YOU START

  • Signed arithmetic and distribution
  • Fractions and percentages

Original educational lesson. Work through the examples before revealing the practice answers. This original lesson supports current GRE General Test study; it does not reproduce official questions, certify a writing score or predict test content.

LEARN THROUGH ORIGINAL PRACTICE

Original GRE-style worked examples and practice

All teaching passages, writing prompts, examples and exercises in this lesson are original. No official ETS questions, prompts or explanations are reproduced. Current structure and observed public sample metadata are separate from this original teaching; no official score or question probability is implied.

01 / UNDERSTAND & APPLY

An equation is a balance with a domain

Adding or subtracting the same expression on both sides preserves equality. Multiplying or dividing both sides by a nonzero constant preserves it too. If dividing by a variable expression, first consider when it could be zero. The goal is to isolate the requested quantity, not necessarily every variable.

A linear equation has its variable only to the first power after simplification. Clear parentheses and combine like terms before deciding whether it has one solution, none, or infinitely many.

02 / UNDERSTAND & APPLY

Keep each transformation reversible

For ax+b=c with a≠0, x=(c−b)/a. Clear fraction denominators using a common multiple when this reduces clutter; multiply every term on both sides. Do not multiply only the terms that visibly contain fractions.

After solving, substitute into the original equation rather than only the last line. That catches dropped signs, denominator mistakes and transcription errors.

ORIGINAL WORKED EXAMPLE

An equation with fractional terms

Solve (2x−1)/3−(x+2)/4=2.

  1. Multiply all terms by 12: 4(2x−1)−3(x+2)=24.
  2. Expand and combine: 8x−4−3x−6=24, so 5x=34.
  3. x=34/5. Substitution gives 21/5−11/5=2.

Answer x=34/5

03 / UNDERSTAND & APPLY

Zero coefficients change the solution count

If simplification gives 0x=0, the equation is an identity for every input in the original domain. If it gives 0x=k with k≠0, it is inconsistent and has no solutions. Do not divide by a coefficient before checking whether it can be zero.

For ax+b=c, a=0 and b=c allows every x; a=0 and b≠c allows none. A parameter question often asks you to identify exactly these boundary values.

ORIGINAL WORKED EXAMPLE

Classify a parameter equation

For which k does kx+4=3x+4 have infinitely many solutions?

  1. Rearrange to (k−3)x=0.
  2. If k≠3, the only solution is x=0.
  3. If k=3, the equation becomes 0=0 for every real x.

Answer k=3

04 / UNDERSTAND & APPLY

Define the variable with its meaning and units

Choose a variable for an unknown quantity and state what it measures. Translate relationships, not word order. “Five less than twice x” means 2x−5; “five less than x, doubled” means 2(x−5). “A is three more than B” means A=B+3.

When a total is fixed, one part can often be written in terms of another: if two ticket counts total 40 and x is the adult count, the child count is 40−x. Do not introduce a second unknown unless it helps.

ORIGINAL WORKED EXAMPLE

Ticket revenue

An event sells 40 tickets. Adult tickets cost $12 and child tickets $7; revenue is $370. How many adult tickets were sold?

  1. Let x be the adult count; children number 40−x.
  2. Revenue is 12x+7(40−x)=370.
  3. 5x+280=370, so x=18. Check: 18·12+22·7=370.

Answer 18 adult tickets

05 / UNDERSTAND & APPLY

Separate a starting amount from a rate

A total cost with a fixed fee follows C=b+rt, where b is the fee and r is cost per unit of usage. The fixed part is paid once; it should not be multiplied by every hour or mile. A total rate can be inferred from a difference in costs because the fixed part cancels.

A linear model is justified only over the range where the stated pricing rule holds. Tiered prices or discounts may require separate cases. A negative mathematical usage solution may show that the requested cost is unattainable under the model.

ORIGINAL WORKED EXAMPLE

Infer a rate and starting fee

A rental costs $34 for 3 hours and $58 for 7 hours, with a fixed fee plus a constant hourly rate. Find both.

  1. The extra 4 hours add $24, so the rate is $6/hour.
  2. At 3 hours, 34=b+6·3, giving b=16.
  3. Check 16+6·7=58.

Answer $16 fixed fee; $6 per hour

06 / UNDERSTAND & APPLY

Keep time frames and conserved quantities aligned

In an age problem, everyone ages by the same number of years. If one person is x now, their age t years ago is x−t. Ratios of ages can change over time even though age differences do not. A statement about past ages must apply the time shift to both people.

In a mixture model, track amount of ingredient, not just concentrations. For idealized additive volumes, mixing x liters of concentration c₁ and V−x liters of concentration c₂ gives c₁x+c₂(V−x)=cV. Every concentration must refer to the same type of amount.

ORIGINAL WORKED EXAMPLE

An age relation at a different time

Mira is 8 years older than Arun. Four years ago, Mira was twice Arun’s age. How old is Arun now?

  1. Let Arun now be a; Mira now is a+8.
  2. Four years ago: a+8−4=2(a−4).
  3. a+4=2a−8, so a=12. Check past ages 8 and 16.

Answer 12 years

07 / UNDERSTAND & APPLY

A valid model needs a plausible solution

A count of objects is usually a nonnegative integer; a length is positive; an elapsed time cannot be negative unless a signed-time coordinate is explicitly used. A decimal algebraic solution to a whole-ticket problem signals either no feasible exact solution or a modeling error.

Check the equation, the units, and the original relationship separately. If the question asks for a difference or total, do not stop at an intermediate variable. Sometimes the requested expression can be isolated directly, saving time.

08 / UNDERSTAND & APPLY

Choose a method and answer the requested question

All examples and practice in this lesson are original. For quantitative comparison (QC), use A if Quantity A is greater, B if Quantity B is greater, C if they are equal, and D if the relationship cannot be determined from the information given. A, B or C must hold for every permitted case. To establish D, give two allowed cases producing different relationships; an inability to calculate is not itself evidence for D.

A single-answer question requires one choice. For multiple-answer questions, obey the stated selection count or select every correct option if instructed. Test each option separately; do not stop after finding one. Multiple-answer questions receive credit only when the complete correct set is selected, with no incorrect choices. Numeric entry requires the requested value, with units handled in the calculation; round only when the question directs you to. A single numeric-entry box accepts an integer or decimal; a pair of fraction boxes accepts an integer numerator and a nonzero integer denominator. Fractions need not be reduced, but reducing makes checks easier. Do not enter a percent sign when the requested number is a percentage. Preserve exact fractions until the last step.

A calculator can check arithmetic but cannot decide the domain, interpretation or denominator for you. Estimate sign and size first, enter parentheses carefully, and compare the result with the original conditions. Cancel factors or exploit structure when doing so is faster and more reliable than decimal entry.

09 / UNDERSTAND & APPLY

Original practice: solve, classify and interpret

State the requested quantity, not merely a variable value.

ORIGINAL PRACTICE · 1

Numeric entry: Solve 4(2x−3)=3x+13.

Reveal answer & reasoning

5

8x−12=3x+13 implies 5x=25, so x=5. Checking gives 28 on both sides.

ORIGINAL PRACTICE · 2

Single answer: 2(x+4)=2x+9 has A one solution x=1; B one solution x=8; C one solution x=9; D no solutions; E infinitely many solutions.

Reveal answer & reasoning

D

Subtract 2x to get 8=9, an impossibility. The disappearance of x alone does not mean infinitely many solutions.

ORIGINAL PRACTICE · 3

Numeric entry: A taxi charges $4 plus $2.50 per mile. A ride costs $29 before any other charges. How many miles?

Reveal answer & reasoning

10

Use 4+2.5m=29; m=25/2.5=10. Dividing 29 by 2.5 would incorrectly spread the fixed charge over mileage.

ORIGINAL PRACTICE · 4

Select all that apply: Which equations express “q is 7 less than three times p”? A q=3p−7; B q+7=3p; C q=3(p−7); D 3p−q=7; E p=3q−7.

Reveal answer & reasoning

A, B and D

A is the direct translation, and B and D are rearrangements. C subtracts 7 before tripling, changing the difference to 21. E reverses the variable roles.

ORIGINAL PRACTICE · 5

QC: 5x+2=17. Quantity A: 2x. Quantity B: 6.

Reveal answer & reasoning

C

The equation gives x=3, so 2x=6. Compare the requested expression, not x itself.

ORIGINAL PRACTICE · 6

Numeric entry: A rectangle has perimeter 46 cm and length 5 cm greater than width. Find width in centimeters.

Reveal answer & reasoning

9

Let width w and length w+5. Then 2w+2(w+5)=46, giving 4w=36 and w=9. Using w+(w+5)=46 would treat perimeter as only half the boundary.

ORIGINAL PRACTICE · 7

Single answer: For which a does ax+6=4x+1 have no solution? A 0; B 1; C 4; D 5; E 6.

Reveal answer & reasoning

C

At a=4, subtracting 4x gives 6=1. At any other a, (a−4)x=−5 has one real solution.

ORIGINAL PRACTICE · 8

Numeric entry: Under an additive-volume model, how many liters of 10% solution must mix with 30% solution to make 8 liters of 25% solution?

Reveal answer & reasoning

2

Let x be liters of 10% solution; the other amount is 8−x. Then 0.10x+0.30(8−x)=0.25·8, giving −0.20x=−0.40 and x=2. The higher concentration supplies 6 liters, so the final value is nearer 30% than 10%.

KEEP THE BIG IDEAS

Quick revision

  • Define variables and units before translating.
  • Multiply every term when clearing denominators.
  • A contradiction means no solution; an identity means all allowed inputs.
  • Substitute into the original conditions and interpret the requested result.
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