ORIGINAL WORKED EXAMPLE
An equation with fractional terms
Solve (2x−1)/3−(x+2)/4=2.
- Multiply all terms by 12: 4(2x−1)−3(x+2)=24.
- Expand and combine: 8x−4−3x−6=24, so 5x=34.
- x=34/5. Substitution gives 21/5−11/5=2.
Answer x=34/5
GRE · Algebra · TOPIC LESSON
Translate relationships into one consistent variable and preserve equivalence while solving.
BY THE END, YOU CAN
BEFORE YOU START
Original educational lesson. Work through the examples before revealing the practice answers. This original lesson supports current GRE General Test study; it does not reproduce official questions, certify a writing score or predict test content.
LEARN THROUGH ORIGINAL PRACTICE
All teaching passages, writing prompts, examples and exercises in this lesson are original. No official ETS questions, prompts or explanations are reproduced. Current structure and observed public sample metadata are separate from this original teaching; no official score or question probability is implied.
01 / UNDERSTAND & APPLY
Adding or subtracting the same expression on both sides preserves equality. Multiplying or dividing both sides by a nonzero constant preserves it too. If dividing by a variable expression, first consider when it could be zero. The goal is to isolate the requested quantity, not necessarily every variable.
A linear equation has its variable only to the first power after simplification. Clear parentheses and combine like terms before deciding whether it has one solution, none, or infinitely many.
02 / UNDERSTAND & APPLY
For ax+b=c with a≠0, x=(c−b)/a. Clear fraction denominators using a common multiple when this reduces clutter; multiply every term on both sides. Do not multiply only the terms that visibly contain fractions.
After solving, substitute into the original equation rather than only the last line. That catches dropped signs, denominator mistakes and transcription errors.
ORIGINAL WORKED EXAMPLE
Solve (2x−1)/3−(x+2)/4=2.
Answer x=34/5
03 / UNDERSTAND & APPLY
If simplification gives 0x=0, the equation is an identity for every input in the original domain. If it gives 0x=k with k≠0, it is inconsistent and has no solutions. Do not divide by a coefficient before checking whether it can be zero.
For ax+b=c, a=0 and b=c allows every x; a=0 and b≠c allows none. A parameter question often asks you to identify exactly these boundary values.
ORIGINAL WORKED EXAMPLE
For which k does kx+4=3x+4 have infinitely many solutions?
Answer k=3
04 / UNDERSTAND & APPLY
Choose a variable for an unknown quantity and state what it measures. Translate relationships, not word order. “Five less than twice x” means 2x−5; “five less than x, doubled” means 2(x−5). “A is three more than B” means A=B+3.
When a total is fixed, one part can often be written in terms of another: if two ticket counts total 40 and x is the adult count, the child count is 40−x. Do not introduce a second unknown unless it helps.
ORIGINAL WORKED EXAMPLE
An event sells 40 tickets. Adult tickets cost $12 and child tickets $7; revenue is $370. How many adult tickets were sold?
Answer 18 adult tickets
05 / UNDERSTAND & APPLY
A total cost with a fixed fee follows C=b+rt, where b is the fee and r is cost per unit of usage. The fixed part is paid once; it should not be multiplied by every hour or mile. A total rate can be inferred from a difference in costs because the fixed part cancels.
A linear model is justified only over the range where the stated pricing rule holds. Tiered prices or discounts may require separate cases. A negative mathematical usage solution may show that the requested cost is unattainable under the model.
ORIGINAL WORKED EXAMPLE
A rental costs $34 for 3 hours and $58 for 7 hours, with a fixed fee plus a constant hourly rate. Find both.
Answer $16 fixed fee; $6 per hour
06 / UNDERSTAND & APPLY
In an age problem, everyone ages by the same number of years. If one person is x now, their age t years ago is x−t. Ratios of ages can change over time even though age differences do not. A statement about past ages must apply the time shift to both people.
In a mixture model, track amount of ingredient, not just concentrations. For idealized additive volumes, mixing x liters of concentration c₁ and V−x liters of concentration c₂ gives c₁x+c₂(V−x)=cV. Every concentration must refer to the same type of amount.
ORIGINAL WORKED EXAMPLE
Mira is 8 years older than Arun. Four years ago, Mira was twice Arun’s age. How old is Arun now?
Answer 12 years
07 / UNDERSTAND & APPLY
A count of objects is usually a nonnegative integer; a length is positive; an elapsed time cannot be negative unless a signed-time coordinate is explicitly used. A decimal algebraic solution to a whole-ticket problem signals either no feasible exact solution or a modeling error.
Check the equation, the units, and the original relationship separately. If the question asks for a difference or total, do not stop at an intermediate variable. Sometimes the requested expression can be isolated directly, saving time.
08 / UNDERSTAND & APPLY
All examples and practice in this lesson are original. For quantitative comparison (QC), use A if Quantity A is greater, B if Quantity B is greater, C if they are equal, and D if the relationship cannot be determined from the information given. A, B or C must hold for every permitted case. To establish D, give two allowed cases producing different relationships; an inability to calculate is not itself evidence for D.
A single-answer question requires one choice. For multiple-answer questions, obey the stated selection count or select every correct option if instructed. Test each option separately; do not stop after finding one. Multiple-answer questions receive credit only when the complete correct set is selected, with no incorrect choices. Numeric entry requires the requested value, with units handled in the calculation; round only when the question directs you to. A single numeric-entry box accepts an integer or decimal; a pair of fraction boxes accepts an integer numerator and a nonzero integer denominator. Fractions need not be reduced, but reducing makes checks easier. Do not enter a percent sign when the requested number is a percentage. Preserve exact fractions until the last step.
A calculator can check arithmetic but cannot decide the domain, interpretation or denominator for you. Estimate sign and size first, enter parentheses carefully, and compare the result with the original conditions. Cancel factors or exploit structure when doing so is faster and more reliable than decimal entry.
09 / UNDERSTAND & APPLY
State the requested quantity, not merely a variable value.
ORIGINAL PRACTICE · 1
5
8x−12=3x+13 implies 5x=25, so x=5. Checking gives 28 on both sides.
ORIGINAL PRACTICE · 2
D
Subtract 2x to get 8=9, an impossibility. The disappearance of x alone does not mean infinitely many solutions.
ORIGINAL PRACTICE · 3
10
Use 4+2.5m=29; m=25/2.5=10. Dividing 29 by 2.5 would incorrectly spread the fixed charge over mileage.
ORIGINAL PRACTICE · 4
A, B and D
A is the direct translation, and B and D are rearrangements. C subtracts 7 before tripling, changing the difference to 21. E reverses the variable roles.
ORIGINAL PRACTICE · 5
C
The equation gives x=3, so 2x=6. Compare the requested expression, not x itself.
ORIGINAL PRACTICE · 6
9
Let width w and length w+5. Then 2w+2(w+5)=46, giving 4w=36 and w=9. Using w+(w+5)=46 would treat perimeter as only half the boundary.
ORIGINAL PRACTICE · 7
C
At a=4, subtracting 4x gives 6=1. At any other a, (a−4)x=−5 has one real solution.
ORIGINAL PRACTICE · 8
2
Let x be liters of 10% solution; the other amount is 8−x. Then 0.10x+0.30(8−x)=0.25·8, giving −0.20x=−0.40 and x=2. The higher concentration supplies 6 liters, so the final value is nearer 30% than 10%.
KEEP THE BIG IDEAS
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