ORIGINAL WORKED EXAMPLE
Substitute an expression
If f(x)=x²−3x, find f(t+2).
- Replace each x by t+2: (t+2)²−3(t+2).
- Expand: t²+4t+4−3t−6.
- Combine to obtain t²+t−2. f(t+2) is not f(t)+2.
Answer t²+t−2
GRE · Algebra · TOPIC LESSON
Connect formulas, coordinate positions and graph features while keeping domains and scales explicit.
BY THE END, YOU CAN
BEFORE YOU START
Original educational lesson. Work through the examples before revealing the practice answers. This original lesson supports current GRE General Test study; it does not reproduce official questions, certify a writing score or predict test content.
LEARN THROUGH ORIGINAL PRACTICE
All teaching passages, writing prompts, examples and exercises in this lesson are original. No official ETS questions, prompts or explanations are reproduced. Current structure and observed public sample metadata are separate from this original teaching; no official score or question probability is implied.
01 / UNDERSTAND & APPLY
An ordered pair (x,y) gives horizontal position first and vertical position second. The axes meet at the origin (0,0). Points on the x-axis have y=0; points on the y-axis have x=0. A labeled scale can use different units on the two axes, so visible steepness alone does not give numerical slope.
GRE coordinate axes and data graphs are drawn to scale, unlike ordinary geometry sketches. Read tick labels and units. The distance between (x₁,y₁) and (x₂,y₂) is √[(x₂−x₁)²+(y₂−y₁)²], and their midpoint averages the two coordinates separately.
02 / UNDERSTAND & APPLY
f(x) names the output of a function at input x; it is not f multiplied by x. Substitute the whole input expression into every x. The domain contains allowed inputs; the range contains resulting outputs. Denominators exclude zero and real square roots require nonnegative radicands.
In a piecewise function, the input chooses the branch. Apply only the formula whose condition contains that input, especially at a boundary. A function can assign the same output to different inputs; it cannot assign two outputs to one input.
ORIGINAL WORKED EXAMPLE
If f(x)=x²−3x, find f(t+2).
Answer t²+t−2
03 / UNDERSTAND & APPLY
For f(g(x)), first calculate g(x), then use its output as the input to f. The order usually matters. The input must belong to g’s domain, and g(x) must belong to f’s domain.
An inverse function, when it exists, reverses the input-output assignment; it is not the reciprocal 1/f(x). For a one-to-one linear function f(x)=ax+b with a≠0, solving y=ax+b for x gives inverse (y−b)/a.
ORIGINAL WORKED EXAMPLE
Let f(x)=2x−1 and g(x)=x². Find f(g(3)) and g(f(3)).
Answer 17 and 25
04 / UNDERSTAND & APPLY
For two points with distinct x-coordinates, slope m=(y₂−y₁)/(x₂−x₁). Keep subtraction order consistent in numerator and denominator. A positive slope rises left to right; a negative slope falls. Horizontal lines have slope zero; vertical lines have undefined slope.
Parallel nonvertical lines have equal slopes. Perpendicular nonvertical lines with nonzero slopes have product −1; a horizontal and vertical pair is perpendicular too. Numerical slope depends on axis units, not just the angle a sketch appears to show.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
ORIGINAL WORKED EXAMPLE
Find the equation through (−2,−3) and (4,9).
Answer y=2x+1
05 / UNDERSTAND & APPLY
For y=mx+b, the y-intercept is (0,b). Find an x-intercept by setting y=0 and solving; if m≠0, its x-coordinate is −b/m. A graph may have several x-intercepts, no x-intercepts, or infinitely many points on an axis.
To find where two graphs intersect, set their y-expressions equal and solve for x, then calculate y. Two line graphs may intersect once, be parallel, or coincide. A line and parabola may intersect at zero, one or two real points.
ORIGINAL WORKED EXAMPLE
Find the intersection of y=2x+1 and y=−x+7.
Answer (2,5)
06 / UNDERSTAND & APPLY
The graph y=|x| is a V with vertex at (0,0). y=|x−h|+k shifts the vertex to (h,k); a negative coefficient reflects it downward. The graph y=(x−h)²+k is an upward parabola with vertex (h,k); multiplying the square by a negative number makes it open downward.
Do not confuse a horizontal shift’s sign: x−3 places the vertex at x=3. Intercepts and sampled points provide checks. A sketch must preserve the declared coordinate scale if used to compare positions.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
ORIGINAL WORKED EXAMPLE
For y=|x−2|−1, find the vertex and x-intercepts.
Answer Vertex (2,−1); x-intercepts (1,0) and (3,0)
07 / UNDERSTAND & APPLY
For y>mx+b, use the boundary line y=mx+b and the region above it; the boundary itself is excluded. For y≥mx+b, include the boundary. A vertical inequality such as x<3 describes points to the left of a vertical boundary.
Test a point not on the boundary when uncertain. For a system, intersect regions; do not keep all points from either region indiscriminately. Reading a graph gives approximate values unless exact coordinates or equations justify precision.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
08 / UNDERSTAND & APPLY
A physical model can restrict a function’s mathematical domain: a cost formula may permit only nonnegative time or whole-item inputs. An apparent line segment on a graph does not authorize extrapolation beyond its stated interval. A graph of paired data does not automatically define a function over every intermediate input.
Calculate distances and slopes from coordinates rather than measuring pixels. A distance formula combines horizontal and vertical lengths in the same physical unit; mismatched units need conversion before geometric distance has meaning.
09 / UNDERSTAND & APPLY
All examples and practice in this lesson are original. For quantitative comparison (QC), use A if Quantity A is greater, B if Quantity B is greater, C if they are equal, and D if the relationship cannot be determined from the information given. A, B or C must hold for every permitted case. To establish D, give two allowed cases producing different relationships; an inability to calculate is not itself evidence for D.
A single-answer question requires one choice. For multiple-answer questions, obey the stated selection count or select every correct option if instructed. Test each option separately; do not stop after finding one. Multiple-answer questions receive credit only when the complete correct set is selected, with no incorrect choices. Numeric entry requires the requested value, with units handled in the calculation; round only when the question directs you to. A single numeric-entry box accepts an integer or decimal; a pair of fraction boxes accepts an integer numerator and a nonzero integer denominator. Fractions need not be reduced, but reducing makes checks easier. Do not enter a percent sign when the requested number is a percentage. Preserve exact fractions until the last step.
A calculator can check arithmetic but cannot decide the domain, interpretation or denominator for you. Estimate sign and size first, enter parentheses carefully, and compare the result with the original conditions. Cancel factors or exploit structure when doing so is faster and more reliable than decimal entry.
10 / UNDERSTAND & APPLY
Use exact coordinates where the equations supply them.
ORIGINAL PRACTICE · 1
10
f(−2)=3·4−2=10. Squaring a parenthesized negative input produces a positive value.
ORIGINAL PRACTICE · 2
A
Slope=(−1−5)/(4−1)=−6/3=−2. Swapping rise and run gives the reciprocal, not slope.
ORIGINAL PRACTICE · 3
4
Set y=0, giving 3x=12. Setting x=0 instead would locate the y-intercept.
ORIGINAL PRACTICE · 4
A, C and E
Substitute each pair into y≥2x−1. A gives 0≥−1, C 3≥3, and E 6≥5. B gives 0<1; D gives −4<−3. Boundary equality is allowed.
ORIGINAL PRACTICE · 5
10
Changes are 6 and 8 cm. Distance=√(36+64)=10 cm. Adding the changes gives a path along two perpendicular segments, not the straight-line distance.
ORIGINAL PRACTICE · 6
C
Both outputs are 9. A function may map different inputs to the same output.
ORIGINAL PRACTICE · 7
6
The input 2 belongs to the second branch because its inequality includes equality. Apply 3·2=6. The excluded first branch would give 7, but its condition x<2 is false at 2; do not apply both formulas or average them.
ORIGINAL PRACTICE · 8
B
The absolute-value term is zero when x=−4, giving y=2. The point (0,6) is on the graph but is not its vertex.
KEEP THE BIG IDEAS
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