Summarize a data set without confusing its typical value, total and variability.
GRE General Test45 min study guide10 indexed sections
BY THE END, YOU CAN
Calculate means, medians, modes, ranges and weighted summaries.
Explain standard deviation as distance from the mean.
Reason about transformations, outliers and incomplete information.
BEFORE YOU START
Fractions and arithmetic
Ordering real numbers
Original educational lesson. Work through the examples before revealing the practice answers. This original lesson supports current GRE General Test study; it does not reproduce official questions, certify a writing score or predict test content.
LEARN THROUGH ORIGINAL PRACTICE
Original GRE-style worked examples and practice
All teaching passages, writing prompts, examples and exercises in this lesson are original. No official ETS questions, prompts or explanations are reproduced. Current structure and observed public sample metadata are separate from this original teaching; no official score or question probability is implied.
01 / UNDERSTAND & APPLY
Identify observations, frequencies and units
A data set is a collection of observations of a specified variable. A frequency tells how often a value occurs; repeated values count repeatedly when finding totals and centers. Record the observation count before dividing. A list of distinct values without their frequencies may not determine the mean.
Units matter: a mean of times is a time; a standard deviation of times is also a time. Variance, the square of standard deviation, uses squared units. A summary does not retain all information about individual observations.
02 / UNDERSTAND & APPLY
The mean balances the total across observations
For n observations, mean=sum/n, so sum=n·mean. This equivalent form makes missing-value and combined-group problems easier. The mean need not be one of the observed values, nor an integer even for integer data.
If a value x is added to a set of n values with mean m, the new mean is (nm+x)/(n+1). Adding a value equal to the mean leaves the mean unchanged; adding one above it raises it, and adding one below lowers it.
ORIGINAL WORKED EXAMPLE
Recover a missing observation
Five delivery times average 18 minutes. Four are 12,17,19,21. Find the fifth.
The five values total 5·18=90 minutes.
The known four total 69 minutes.
The missing time is 90−69=21 minutes.
Answer 21 minutes
03 / UNDERSTAND & APPLY
Weight each value by its number of observations
A weighted mean is Σ(weight×value)/Σweights. For group means, the weights are group sizes. The mean of group means is valid only if group sizes are equal, or a special coincidence makes it so. Positive weights force the result to lie between the smallest and largest group means.
Frequency tables use exactly the same method: value×frequency contributes to the total, and frequencies add to the number of observations. Do not divide by the number of table rows.
ORIGINAL WORKED EXAMPLE
Combine unequal groups
A class of 12 students averages 80 points; another of 18 averages 70. Find the combined average.
Group totals are 12·80=960 and 18·70=1260.
Total points=2220 for 30 students.
Mean=2220/30=74. It is closer to 70 because that group is larger.
Answer 74 points
04 / UNDERSTAND & APPLY
Position and frequency answer different questions
Sort data before finding the median. With odd n, it is the middle value at position (n+1)/2. With even n, it is the average of values at positions n/2 and n/2+1. The median splits the ordered positions; tied values can appear on both sides.
The mode is a most frequent value. A set can have multiple modes, and depending on the stated convention can have no mode when nothing is more frequent. The mode describes frequency, not numerical size. Mean, median and mode can coincide, but need not.
ORIGINAL WORKED EXAMPLE
Three centers of one list
For 2,4,4,7,13, find mean, median and mode.
The sum is 30, so mean=30/5=6.
The sorted middle value is 4, so median=4.
The value 4 occurs twice, more often than any other value, so mode=4.
Answer Mean 6; median 4; mode 4
05 / UNDERSTAND & APPLY
The range uses only two observations
Range=maximum−minimum and is nonnegative. It uses only the endpoints, so two sets can share a range while clustering very differently inside it. An extreme observation can greatly increase range while leaving median unchanged.
Spread and center are separate. Translating every value by the same amount moves the center but leaves pairwise distances unchanged. A set with a larger mean need not have a larger range or standard deviation.
06 / UNDERSTAND & APPLY
Standard deviation measures typical deviation from the mean
For a full finite distribution treated as a population, variance is the mean of squared deviations from the mean; population standard deviation is its nonnegative square root: σ=√[Σ(xᵢ−μ)²/n]. Squaring prevents positive and negative deviations from cancelling. For sample standard deviation, a common convention divides by n−1 instead; use the definition supplied by a calculation question.
The GRE emphasizes interpreting standard deviation and comparing spread rather than elaborate computation. Standard deviation is zero exactly when all observations equal the mean. Values farther from the mean generally contribute more through squared deviations, so an outlier can have a large effect.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
Both horizontal axes use the same one-unit scale. The sets have the same mean, but A has larger range and standard deviation. Dot height carries no numerical meaning.
ORIGINAL WORKED EXAMPLE
Calculate a population standard deviation
Treat 2,2,6,6 as an entire population. Find its standard deviation.
The mean is 4. Deviations are −2,−2,2,2.
Their squared deviations sum to 16; population variance=16/4=4.
The standard deviation is √4=2, in the original units.
Answer 2
07 / UNDERSTAND & APPLY
Shift and scale rules follow from deviations
Adding c to every observation adds c to mean and median, but leaves range and standard deviation unchanged. Multiplying every observation by k multiplies mean by k and standard deviation and range by |k|. A negative multiplier reverses order, but distances remain nonnegative.
Changing a single observation is different from transforming every observation. Adding the same value to the list as a new observation also differs from adding it to each old value. Read the operation precisely.
ORIGINAL WORKED EXAMPLE
Convert both center and spread
Temperatures have mean 20°C and population standard deviation 3°C. Convert using F=1.8C+32.
The mean transforms linearly: 1.8·20+32=68°F.
The standard deviation is multiplied by |1.8| but is not shifted by 32.
The new standard deviation is 1.8·3=5.4°F.
Answer Mean 68°F; standard deviation 5.4°F
08 / UNDERSTAND & APPLY
A summary can conceal the change you care about
Moving the largest observation still farther right usually raises the mean and range while leaving the median fixed if its ordered position does not change. Median is more resistant to extreme values, but is not immune to every change in data.
A claim that one set is “more variable” needs a named measure and sufficient information. The same mean, median or range does not fix standard deviation. In QC, construct two data sets satisfying the summaries before deciding whether the comparison is forced.
09 / UNDERSTAND & APPLY
Choose a method and answer the requested question
All examples and practice in this lesson are original. For quantitative comparison (QC), use A if Quantity A is greater, B if Quantity B is greater, C if they are equal, and D if the relationship cannot be determined from the information given. A, B or C must hold for every permitted case. To establish D, give two allowed cases producing different relationships; an inability to calculate is not itself evidence for D.
A single-answer question requires one choice. For multiple-answer questions, obey the stated selection count or select every correct option if instructed. Test each option separately; do not stop after finding one. Multiple-answer questions receive credit only when the complete correct set is selected, with no incorrect choices. Numeric entry requires the requested value, with units handled in the calculation; round only when the question directs you to. A single numeric-entry box accepts an integer or decimal; a pair of fraction boxes accepts an integer numerator and a nonzero integer denominator. Fractions need not be reduced, but reducing makes checks easier. Do not enter a percent sign when the requested number is a percentage. Preserve exact fractions until the last step.
A calculator can check arithmetic but cannot decide the domain, interpretation or denominator for you. Estimate sign and size first, enter parentheses carefully, and compare the result with the original conditions. Cancel factors or exploit structure when doing so is faster and more reliable than decimal entry.
10 / UNDERSTAND & APPLY
Original practice: totals, positions and spread
When standard deviation must be calculated, the question explicitly supplies the population convention.
ORIGINAL PRACTICE · 1
Numeric entry: Six numbers have mean 9. Five total 41. Find the sixth.
Reveal answer & reasoning
13
The total of all six is 54, so the missing value is 54−41=13. A mean is not the total.
ORIGINAL PRACTICE · 2
Single answer: The median of 9,2,5,11,3,8 is A 5; B 6; C 6.5; D 7; E 8.
Reveal answer & reasoning
C: 6.5
Sort: 2,3,5,8,9,11. Average the third and fourth values: (5+8)/2=6.5. Taking the middle values of the unsorted list is invalid.
ORIGINAL PRACTICE · 3
Numeric entry: Values 1,4,7 have frequencies 2,3,5. Find the mean.
Reveal answer & reasoning
4.9
Total=1·2+4·3+7·5=49; count=10; mean=4.9. Dividing by three rows would use the wrong denominator.
ORIGINAL PRACTICE · 4
Select all that apply: Adding 6 to every observation changes which summaries by exactly +6? A mean; B median; C range; D population standard deviation; E minimum.
Reveal answer & reasoning
A, B and E
Every location shifts by 6, including the minimum and middle values. Differences and deviations stay the same, so range and standard deviation do not increase.
ORIGINAL PRACTICE · 5
QC: Set A is 1,5,9. Set B is 4,5,6. Quantity A: population standard deviation of set A. Quantity B: that of set B.
Reveal answer & reasoning
A
Both means are 5. A has deviations −4,0,4 versus −1,0,1 for B, so its squared-deviation average is larger. Comparing means would not settle spread.
ORIGINAL PRACTICE · 6
Numeric entry: The population 3,3,3,3 has what standard deviation?
Reveal answer & reasoning
0
Every deviation from the mean 3 is zero. The mean being positive does not imply any spread.
ORIGINAL PRACTICE · 7
QC: A set has mean 10. Quantity A: its median. Quantity B: 10.
Reveal answer & reasoning
D
The set 0,0,30 has mean 10 and median 0; the set 0,15,15 has mean 10 and median 15. Thus the mean alone does not determine the median relationship.
ORIGINAL PRACTICE · 8
Numeric entry: A group of 8 observations has mean 15; a group of 2 has mean 25. Find the combined mean.
Reveal answer & reasoning
17
Total=8·15+2·25=170 across 10 observations; mean=17. The unweighted mean 20 would treat unequal groups as equal size.
KEEP THE BIG IDEAS
Quick revision
Recover totals with count×mean before combining groups.
Sort before locating the median and retain frequencies.
Spread is separate from center; standard deviation measures deviations.
Shifts leave spread unchanged, while scaling multiplies spread by the absolute factor.
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