ORIGINAL WORKED EXAMPLE
Apply the idea
A bag contains only red and blue beads in ratio 3:5. There are 64 beads. How many are red?
- The total is 3+5=8 ratio units.
- One ratio unit is 64/8=8 beads.
- Red accounts for 3 units, or 24 beads.
Answer 24.
GMAT · Ratios, proportions and percentages · TOPIC LESSON
Original GMAT Problem Solving instruction: reason from constraints, calculate efficiently without a calculator, and check the requested quantity.
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01 / UNDERSTAND & APPLY
A ratio compares quantities in a stated order. If red:blue=3:5, write red=3k and blue=5k for a common scale k. Red is 3/5 of blue but 3/8 of the combined total. The denominator in a fraction must name its reference quantity.
A ratio alone gives relative size, not actual counts. For a displayed positive ratio such as 3:5, the scale k is positive. For counts, it must also make every category an integer; for lengths or masses, k may be nonintegral. A scale of zero would create 0:0, not the stated ratio. Keep units consistent before comparing like quantities.
ORIGINAL WORKED EXAMPLE
A bag contains only red and blue beads in ratio 3:5. There are 64 beads. How many are red?
Answer 24.
ORIGINAL PRACTICE · 1
3/10.
The whole has 7+3=10 equal ratio units, of which 3 are designers. The value 3/7 compares designers with analysts, not with the entire team.
02 / UNDERSTAND & APPLY
Multiplying every part of a ratio by the same positive factor preserves the relationship. To recover quantities, locate a total, difference or known part that determines the scale. A difference of ratio units is as useful as a sum.
If a ratio is given in fractions, multiply all entries by a common denominator, then reduce. Scaling only one entry changes the relationship. Ratios can express measurements that are not integers even when the simplified entries are integers.
ORIGINAL WORKED EXAMPLE
The lengths of two cables are in ratio 4:7, and the longer exceeds the shorter by 18 metres. Find both lengths.
Answer 24 metres and 42 metres.
ORIGINAL PRACTICE · 1
4:5.
Multiply both entries by 6, giving 4 and 5. Dividing 2 by 5 and ignoring the denominators would compare different-sized fractional units.
03 / UNDERSTAND & APPLY
When a:b and b:c are given, the two appearances of b must refer to the same amount. Scale the ratios until their b entries match, then assemble a:b:c. The least common multiple often gives the smallest convenient alignment.
Simply copying the outer entries can fail because each original ratio may use a different scale. If the shared quantity is zero, ratios involving division by it are not defined; ordinary positive-ratio problems avoid this by stating positive quantities.
ORIGINAL WORKED EXAMPLE
If a:b=2:3 and b:c=4:5, find a:c.
Answer 8:15.
ORIGINAL PRACTICE · 1
3:8:14.
Double the second ratio to y:z=8:14, then join at y=8. The unscaled list 3:8:7 contradicts the stated y:z ratio.
04 / UNDERSTAND & APPLY
Direct variation y=kx keeps y/x constant: doubling x doubles y. Inverse variation y=k/x keeps xy constant: doubling x halves y. The wording must justify the model; two quantities changing together do not automatically vary directly.
For a fixed job performed by identical workers at constant independent rates, workers×time is constant. If efficiency changes, or there is fixed setup time, this inverse model may not hold. Write the invariant and its assumptions before calculating.
ORIGINAL WORKED EXAMPLE
Six identical machines complete a fixed batch in 15 hours. How long would 10 such machines take if rates remain constant?
Answer 9 hours.
ORIGINAL PRACTICE · 1
30.
The constant is y/x=18/12=3/2. Thus y=(3/2)×20=30. Inverse variation would predict 10.8, but it contradicts the stated direct model.
05 / UNDERSTAND & APPLY
A conversion factor such as 100 centimetres/1 metre equals 1 in physical quantity. Multiply so unwanted units cancel. For rates, convert both numerator and denominator as needed; an hour-to-minute conversion affects the denominator inversely.
A conversion of a squared or cubed unit must also be squared or cubed. This is unit arithmetic, not a geometry assumption: since 1 metre=100 centimetres, 1 square metre=10,000 square centimetres. Always carry the unit through the line of arithmetic.
ORIGINAL WORKED EXAMPLE
Convert 72 kilometres per hour to metres per second.
Answer 20 metres per second.
ORIGINAL PRACTICE · 1
1,000 millilitres.
20 seconds is 1/3 minute, so the volume is 3×1/3=1 litre=1,000 millilitres. Multiplying by 20 without converting seconds overstates the amount by a factor of 60.
06 / UNDERSTAND & APPLY
Both sides of an equation must represent the same type of quantity. Rate×time gives amount; distance/rate gives time. Adding dollars to hours is meaningless. Units can reveal that an algebraic arrangement is wrong before any arithmetic is done.
Matching units is necessary but not sufficient: two different formulas can both have the correct units. You still need the underlying relationship. A per-person average must multiply by a person count to recover a total.
ORIGINAL WORKED EXAMPLE
A printer produces 18 pages per minute. Which operation gives the minutes needed for 450 pages?
Answer 450÷18=25 minutes.
ORIGINAL PRACTICE · 1
$4.20.
600 grams=0.6 kilogram. Multiply $7/kg by 0.6 kg to get $4.20. The tempting $4,200 treats grams as kilograms; dividing price by mass does not produce dollars.
07 / UNDERSTAND & APPLY
Adding or removing members changes both a part and sometimes the total. Introduce one scale for the original ratio, then express the final quantities explicitly. Do not assume the original scale also measures one unit of the new ratio.
If the same amount is added to both positive parts of an unequal ratio, their ratio moves toward 1; it does not stay constant. This directional check can catch a reversed equation. Removing members also requires nonnegative final counts.
ORIGINAL WORKED EXAMPLE
A box has red:blue=2:5. After adding 9 red counters and no blue counters, the ratio becomes 1:1. How many blue counters were originally present?
Answer 15.
ORIGINAL PRACTICE · 1
28.
Write original counts 3k and 4k. Then (3k+6)/(4k)=9/8, so 24k+48=36k and k=4. The original total is 7×4=28. Doubling ratio entries without adjusting the scale can produce the tempting but incorrect 56.
08 / UNDERSTAND & APPLY
Ratios often invite an attractive answer to the wrong comparison: part divided by the other part instead of part divided by the whole. Label the numerator and denominator in words before substituting numbers.
When a problem gives only relative information, a convenient total can simplify computation. Choose a multiple of the ratio-unit sum for count models. This shortcut works for a scale-invariant requested fraction, not for an absolute count unless a scale is given.
ORIGINAL WORKED EXAMPLE
If a mixture contains oil:water=2:3, what fraction of the mixture is water after adding water equal to the original oil amount?
Answer 5/7.
ORIGINAL PRACTICE · 1
2/5.
The difference is 2 ratio units, measured against A=5 units. Using 2/7 measures the difference against B; using 2/12 measures it against the combined total. The wording determines the base.
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