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SAT · Problem-Solving and Data Analysis · TOPIC LESSON

Inference from sample statistics and margin of error

Use a representative sample to estimate a population and express the uncertainty honestly.

SAT35 min study guide9 indexed sections

BY THE END, YOU CAN

  • Estimate population proportions, counts and means from sample statistics.
  • Interpret a stated margin of error and confidence interval.
  • Explain how sample size affects precision under comparable conditions.

BEFORE YOU START

  • Means, proportions and percentages.
  • Distinction between a sample and a population.

Original educational lesson. Work through the examples before revealing the practice answers. This lesson supports SAT Math and Reading and Writing skill study; it does not reproduce official questions or guarantee a score.

LEARN THROUGH ORIGINAL PRACTICE

Original SAT-style worked examples and practice

The teaching passages, worked examples and exercises in this lesson are original. They are not official College Board questions or past-exam reproductions. Blueprint and observed-practice analytics describe separate factual metadata; those source questions are not displayed here.

01 / UNDERSTAND & APPLY

A sample statistic estimates a population quantity

The population is the full group of interest; the sample is the subset measured. A statistic, such as a sample mean or proportion, is computed from the sample. A population parameter describes the whole group. Inference uses the statistic as evidence about the parameter, while acknowledging sampling uncertainty.

A random sample from a well-defined population supports generalization to that population if the sampling and response process is sound. A large convenience sample can still be biased. Population membership must match the group actually sampled.

02 / UNDERSTAND & APPLY

Estimate a proportion and then a count

The sample proportion is observed successes/sample size. To estimate a population count, multiply the sample proportion by the population size. This produces an estimate, not an exact count, because a different random sample could give a different proportion.

ORIGINAL WORKED EXAMPLE

Scale a sample proportion

In a random sample of 200 residents, 74 favor a proposed park. Estimate how many of the town’s 5,000 residents favor it.

  1. The sample proportion is 74/200 = 0.37.
  2. Apply that estimated proportion to the population: 0.37 × 5000 = 1850.
  3. The result is an estimate based on representativeness, not a count of every resident.

Answer About 1,850 residents

03 / UNDERSTAND & APPLY

A sample mean can estimate a population mean

A representative sample mean estimates the population’s average, not each individual value. Multiplying the estimated average by population size can estimate a population total when the measurement applies to every member and the population size is known.

Do not multiply a mean by the sample size if the requested total is for the entire population. Conversely, do not mistake the population total for the average.

ORIGINAL WORKED EXAMPLE

Estimate a total from a mean

A random sample of 50 trees has mean fruit yield 18 kg. Estimate the total yield of 320 comparable trees in the sampled orchard.

  1. Use 18 kg as the estimate of average yield per tree.
  2. Multiply by 320 trees: 18 × 320 = 5760 kg.
  3. The sampled orchard defines the population to which the estimate applies.

Answer About 5,760 kg

04 / UNDERSTAND & APPLY

Margin of error belongs to the estimate

A reported estimate ± margin of error gives an interval around the estimate at a stated confidence level and under the procedure’s assumptions. For a proportion expressed as 58% with margin 4 percentage points, the interval is 54% to 62%; the margin is an additive width, not 4% of 58%.

The margin addresses random sampling variation under the model. It does not automatically include nonresponse, poorly worded questions, undercoverage or measurement error. A biased procedure can produce a narrow interval around the wrong target.

Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.

An estimate and its margin of errorA proportion estimate of 58% with margin of error 4 percentage points gives an interval from 54% to 62%. A second estimate of 58% with margin 2 percentage points gives 56% to 60%.50%52%54%56%58%60%62%64%58% ± 4 percentage points58% ± 2 percentage points
At the same confidence level and under comparable sampling conditions, a narrower interval is more precise. Neither interval guarantees that a particular individual has the estimated outcome.

ORIGINAL WORKED EXAMPLE

Read a reported interval

A survey estimates support at 58% with margin of error 4 percentage points. What interval is reported?

  1. Subtract the margin: 58% − 4 percentage points = 54%.
  2. Add the margin: 58% + 4 percentage points = 62%.
  3. The interval describes uncertainty in the population support proportion, not a range of individual opinions.

Answer 54% to 62%

05 / UNDERSTAND & APPLY

Confidence describes the procedure over repeated samples

A 95% confidence procedure is designed so that, over many repeated samples taken and analyzed in the same way, about 95% of the resulting intervals contain the true fixed population parameter. For a particular completed interval, the fixed parameter either is or is not inside it.

A confidence interval for a population mean does not claim that 95% of individuals lie in it. It also does not guarantee that the sample mean equals the population mean. Interpret uncertainty in the parameter being estimated.

06 / UNDERSTAND & APPLY

Decide what an interval supports

An estimate is the center, while the interval communicates a range of values compatible with the procedure at the stated confidence level. If an interval includes 50%, an estimate slightly above 50% alone does not establish that population support exceeds half at that confidence level.

Overlapping individual confidence intervals are not a universal formal test of whether two populations differ. A direct comparison generally needs an interval or test for their difference and an appropriate design.

ORIGINAL WORKED EXAMPLE

A majority claim needs more than a point estimate

A poll reports 52% support with margin of error 5 percentage points. Does the stated interval support an unqualified claim that a majority of the population favors the proposal?

  1. The interval is 47% to 57%.
  2. Values below and above 50% lie inside it.
  3. The point estimate suggests a majority, but the stated uncertainty does not establish one.

Answer No; the reported interval includes support below 50%

07 / UNDERSTAND & APPLY

Larger random samples usually improve precision

Under comparable random-sampling conditions, the same confidence level and a population large relative to the sample, margin of error typically scales approximately as 1/√n. Quadrupling sample size roughly halves the margin; merely doubling it does not halve the margin.

This approximation assumes comparable variability and design. Sampling without replacement from a substantial fraction of a small population can require a finite-population adjustment. The essential distinction is precision versus bias: more observations reduce random error but do not fix a systematically unrepresentative method.

ORIGINAL WORKED EXAMPLE

Plan a smaller margin

A comparable survey of 400 randomly sampled people has margin about 6 percentage points. Approximately how large a sample would halve that margin at the same confidence level?

  1. To halve a quantity proportional to 1/√n, double √n.
  2. That requires multiplying n by 4.
  3. The target is approximately 4 × 400 = 1600 people.

Answer About 1,600 people

08 / UNDERSTAND & APPLY

Carry uncertainty through a population estimate

If a population has 8,000 members and the plausible proportion interval is 0.31 to 0.39, multiplying both endpoints gives estimated counts 2,480 to 3,120. These are interval-based estimates, not verified exact counts. If rounding is requested, delay it until after multiplication.

Calculator arithmetic can evaluate endpoints, but cannot decide whether the sample represents the target population or whether a reported margin addresses all important sources of error.

09 / UNDERSTAND & APPLY

Original practice: parameter, estimate and uncertainty

Use the reported assumptions rather than inventing certainty.

ORIGINAL PRACTICE · 1

A random sample has 36 successes out of 120. Estimate the population proportion.

Reveal answer & reasoning

0.30 or 30%

The sample proportion is 36/120.

ORIGINAL PRACTICE · 2

Use a 30% estimate for a population of 900. Estimate the count.

Reveal answer & reasoning

270

Multiply 0.30 × 900, while retaining the interpretation as an estimate.

ORIGINAL PRACTICE · 3

A mean estimate is 42 with margin 3. Give the interval.

Reveal answer & reasoning

39 to 45

Subtract and add the margin to the estimate.

ORIGINAL PRACTICE · 4

An estimate is 64% ± 2 percentage points. Is the lower endpoint 62% or 62.72%?

Reveal answer & reasoning

62%

Percentage-point margins are additive; they are not 2% of the estimate.

ORIGINAL PRACTICE · 5

Under comparable conditions, how does quadrupling n affect margin of error?

Reveal answer & reasoning

It roughly halves it

1/√(4n) is half of 1/√n.

ORIGINAL PRACTICE · 6

Does increasing a biased convenience sample from 100 to 10,000 necessarily remove its bias?

Reveal answer & reasoning

No

Larger size reduces random variation but does not repair the selection mechanism.

ORIGINAL PRACTICE · 7

A 95% confidence interval for average weight is 61 to 65 kg. Does it contain 95% of individual weights?

Reveal answer & reasoning

Not necessarily

The interval estimates a population mean, not the distribution of individuals.

ORIGINAL PRACTICE · 8

A poll gives 49% ± 4 points. Does its interval include 50%?

Reveal answer & reasoning

Yes

The interval is 45% to 53%, which contains 50%.

ORIGINAL PRACTICE · 9

A population has 2,000 items and estimated defect proportion 0.08 ± 0.02. Give the interval-based estimated defect count.

Reveal answer & reasoning

120 to 200

The proportion interval is 0.06 to 0.10; multiply each endpoint by 2,000.

KEEP THE BIG IDEAS

Quick revision

  • A statistic estimates a clearly defined population parameter.
  • Margin of error measures sampling uncertainty under assumptions, not every possible bias.
  • Larger samples improve precision under comparable conditions; random selection supports generalization.
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