SAT · Problem-Solving and Data Analysis · TOPIC LESSON
Ratios, rates, proportional relationships, and units
Keep quantities proportional and let units guide every conversion.
SAT35 min study guide10 indexed sections
BY THE END, YOU CAN
Use ratios, rates and proportions in multistep contexts.
Interpret scale drawings and derived units.
Convert lengths, areas, volumes and compound rates correctly.
BEFORE YOU START
Fractions, multiplication and division.
Solving a one-variable equation.
Original educational lesson. Work through the examples before revealing the practice answers. This lesson supports SAT Math and Reading and Writing skill study; it does not reproduce official questions or guarantee a score.
LEARN THROUGH ORIGINAL PRACTICE
Original SAT-style worked examples and practice
The teaching passages, worked examples and exercises in this lesson are original. They are not official College Board questions or past-exam reproductions. Blueprint and observed-practice analytics describe separate factual metadata; those source questions are not displayed here.
01 / UNDERSTAND & APPLY
A ratio compares quantities in a stated order
The ratio a:b means a/b when b ≠ 0; it does not by itself state the total. If red:blue = 3:5, write red = 3k and blue = 5k, so total = 8k. Red is 3/8 of the total, not 3/5. Keep the order attached to the quantity names.
Equivalent ratios multiply both quantities by the same factor. Adding the same number to both does not generally preserve a ratio.
02 / UNDERSTAND & APPLY
Split a total by ratio parts
Add the ratio parts, divide the total by that sum to find the size of one part, then multiply by each component. Whole-number objects require whole-number counts; a model with fractional counts may be incompatible with the context.
ORIGINAL WORKED EXAMPLE
Part-to-part versus part-to-whole
A mosaic has 72 tiles with green:white = 5:7. How many green tiles are there?
The total ratio is 5 + 7 = 12 parts.
Each part represents 72/12 = 6 tiles.
Green uses 5 parts: 5 × 6 = 30.
The green fraction of all tiles is 5/12, not 5/7.
Answer 30 green tiles
03 / UNDERSTAND & APPLY
Proportional relationships pass through the origin
A direct proportional relationship is y = kx, with a constant ratio y/x = k for nonzero x. A fixed starting fee makes y = kx + b nonproportional when b ≠ 0 even though it remains linear. Use a proportion only when the underlying rate or scale is constant.
ORIGINAL WORKED EXAMPLE
Scale a recipe
A recipe uses 450 g of flour for 12 rolls. At the same recipe ratio, how much flour is needed for 20 rolls?
The flour rate is 450/12 = 37.5 grams per roll.
Multiply by 20 rolls: 37.5 × 20 = 750 grams.
Equivalently 450/12 = F/20, so 12F = 9000.
Answer 750 g
04 / UNDERSTAND & APPLY
A rate includes units in its denominator
Speed is distance/time, density is mass/volume, and a unit price is cost/quantity. State which quantity is “per” which. If a vehicle travels equal distances at two different speeds, averaging the speeds directly is wrong because it spends different amounts of time at those speeds. Total average speed is always total distance divided by total time.
ORIGINAL WORKED EXAMPLE
Average speed from totals
A cyclist travels 18 km in 1 hour and then 12 km in 0.5 hour. What is the average speed for the whole trip?
Add distances: 18 + 12 = 30 km.
Add times: 1 + 0.5 = 1.5 hours.
Divide total distance by total time: 30/1.5 = 20 km/h.
The segment speeds 18 and 24 km/h cannot be averaged equally because their durations differ.
Answer 20 km/h
05 / UNDERSTAND & APPLY
Use conversion factors equal to one
A conversion factor represents equal quantities in different units, such as 100 cm/1 m. Arrange it so the unwanted unit cancels. In a multistep conversion, keep units through the full product and round only at the end if needed.
When the unit is in a denominator, its conversion direction reverses. Converting “per minute” to “per hour” multiplies the numerical rate by 60, whereas converting a duration in minutes to hours divides by 60.
ORIGINAL WORKED EXAMPLE
Convert a compound rate
Convert 7.5 meters per second to kilometers per hour.
Start with 7.5 m/s.
Multiply by 1 km/1000 m and 3600 s/1 h.
Meters and seconds cancel, leaving 7.5 × 3600/1000 = 27 km/h.
Answer 27 km/h
06 / UNDERSTAND & APPLY
Read a scale as a length relationship
A scale drawing gives corresponding lengths, not areas directly. If a drawing uses 1 cm for 3 m, multiply drawing lengths by 3 m/cm. For same-unit similar shapes with length ratio k, perimeter scales by k, area by k² and volume by k³. A two-dimensional drawing can encode a three-dimensional object only when the needed dimensions are given.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
Convert each length using the stated scale. The real area is 18 × 12 = 216 m²; a length factor must be squared when converting area.
ORIGINAL WORKED EXAMPLE
Convert an area from a drawing
A garden is shown as 6 cm by 4 cm at scale 1 cm : 3 m. Find its real area.
The real length is 6 × 3 = 18 m and width is 4 × 3 = 12 m.
Multiply: 18 × 12 = 216 m².
The drawing area is 24 cm²; each cm² represents 3² = 9 m², so 24 × 9 confirms 216.
Answer 216 m²
07 / UNDERSTAND & APPLY
Square and cube the unit conversion
Because 1 m = 100 cm, 1 m² = (100 cm)² = 10,000 cm² and 1 m³ = 1,000,000 cm³. Applying a length conversion only once to an area or volume is a dimensional error. Density conversions combine a mass conversion with a cubed length conversion.
ORIGINAL WORKED EXAMPLE
Volume conversion
Convert 0.08 m³ to cm³.
One meter contains 100 centimeters.
Therefore one cubic meter contains 100³ = 1,000,000 cubic centimeters.
Multiply 0.08 by 1,000,000.
Answer 80,000 cm³
08 / UNDERSTAND & APPLY
Derived units can multiply quantities
Some derived units are products rather than quotients. Energy in kilowatt-hours equals power in kilowatts multiplied by operating time in hours. A kilowatt measures a rate of energy use; a kilowatt-hour measures an amount of energy. Do not treat kW and kWh as interchangeable.
If an appliance changes power level, add the energy used during each interval rather than multiplying one rate by the entire time.
ORIGINAL WORKED EXAMPLE
Power multiplied by time
A heater runs at 1.8 kW for 2 hours and then at 0.6 kW for 3 hours. How much electrical energy does it use?
During the first interval, energy is 1.8 kW × 2 h = 3.6 kWh.
During the second interval, energy is 0.6 kW × 3 h = 1.8 kWh.
Add energy amounts: 3.6 + 1.8 = 5.4 kWh.
The average power over all 5 hours is 5.4 kWh / 5 h = 1.08 kW, a different quantity.
Answer 5.4 kWh
09 / UNDERSTAND & APPLY
Reasonableness and reciprocal traps
A quantity expressed in a smaller unit has a larger numerical count: 2 m is 200 cm. The physical length stays the same. A rate can change in the opposite numerical direction if the smaller unit is in its denominator, so use cancellation instead of that heuristic alone.
Calculator arithmetic helps with several factors, but only a correctly arranged model gives meaningful units. Compare magnitude with a rough estimate; a walking speed of thousands of kilometers per hour signals a conversion error.
10 / UNDERSTAND & APPLY
Original practice: show the unit cancellation
Keep exact values until the final step.
ORIGINAL PRACTICE · 1
Red:blue = 2:3 and total = 45. How many blue?
Reveal answer & reasoning
27
There are 5 parts, each 9; blue uses 3 parts.
ORIGINAL PRACTICE · 2
Five identical notebooks cost $17.50. What is the price per notebook?
Reveal answer & reasoning
$3.50
Divide cost by count: 17.50/5 = 3.50 dollars per notebook.
ORIGINAL PRACTICE · 3
Is y = 4x + 9 a direct proportion?
Reveal answer & reasoning
No
A direct proportion has form y = kx and goes through the origin; this rule has a fixed offset 9.
ORIGINAL PRACTICE · 4
Convert 90 cm to meters.
Reveal answer & reasoning
0.9 m
Multiply by 1 m/100 cm, giving 90/100 m.
ORIGINAL PRACTICE · 5
Convert 2.5 hours to minutes.
Reveal answer & reasoning
150 minutes
Multiply by 60 minutes per hour.
ORIGINAL PRACTICE · 6
Convert 3 m² to cm².
Reveal answer & reasoning
30,000 cm²
The length factor 100 must be squared: 3 × 100².
ORIGINAL PRACTICE · 7
A substance has mass 420 g and volume 70 cm³. Find its density.
Reveal answer & reasoning
6 g/cm³
Density is mass divided by volume: 420/70.
ORIGINAL PRACTICE · 8
A model has length scale 1:4 compared with the real object. What is its volume ratio?
Reveal answer & reasoning
1:64
For similar three-dimensional objects, cube the length ratio: 1³:4³.
ORIGINAL PRACTICE · 9
A pump delivers 15 liters in 40 seconds at a constant rate. How much in 2 minutes?
Reveal answer & reasoning
45 liters
Two minutes is 120 seconds, three times the measured interval, so volume triples.
KEEP THE BIG IDEAS
Quick revision
Attach quantity names and units to every ratio.
A proportional model requires a constant ratio and no fixed offset.
Length conversion factors must be squared or cubed for area or volume.
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