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SAT · Problem-Solving and Data Analysis · TOPIC LESSON

Percentages

Identify the base, use multipliers, and distinguish relative change from percentage points.

SAT35 min study guide9 indexed sections

BY THE END, YOU CAN

  • Find a part, whole or percentage from the other two.
  • Model increases, decreases, successive changes and reverse percentages.
  • Interpret percentages above 100% and common financial contexts.

BEFORE YOU START

  • Fractions and decimal arithmetic.
  • Solving one-variable equations.

Original educational lesson. Work through the examples before revealing the practice answers. This lesson supports SAT Math and Reading and Writing skill study; it does not reproduce official questions or guarantee a score.

LEARN THROUGH ORIGINAL PRACTICE

Original SAT-style worked examples and practice

The teaching passages, worked examples and exercises in this lesson are original. They are not official College Board questions or past-exam reproductions. Blueprint and observed-practice analytics describe separate factual metadata; those source questions are not displayed here.

01 / UNDERSTAND & APPLY

Percent means per hundred of a base

A percentage p% is the fraction p/100 of a specified base. The relationship part = rate × whole becomes A = (p/100)B. Before calculating, name the base B: “20% of B” and “B is 20% of A” are different statements. Percentages can exceed 100 when the compared quantity is larger than the base.

The question may ask for the part, the whole or the rate. Solve the same relationship for the requested quantity instead of memorizing unrelated formulas.

02 / UNDERSTAND & APPLY

Find the missing member of the relationship

To find a part, multiply by the decimal rate. To find the base, divide the part by the decimal rate. To find a percentage, divide part by base and multiply by 100. The denominator must be the specified reference quantity.

ORIGINAL WORKED EXAMPLE

Recover the original whole

A class has 18 students who bike to school, representing 30% of the class. How many students are in the class?

  1. Let N be the class size. The relationship is 18 = 0.30N.
  2. Divide by 0.30: N = 60.
  3. Check: 30% of 60 is 18.

Answer 60 students

03 / UNDERSTAND & APPLY

Turn a change into a multiplier

An increase of r as a decimal changes B to B + rB = (1 + r)B. A decrease changes it to B − rB = (1 − r)B. A 12% increase uses 1.12; a 12% decrease uses 0.88. The percent change from old to new is (new − old)/old × 100%.

The old value is the base for a change, even if the new value is larger or easier to divide by.

ORIGINAL WORKED EXAMPLE

Compute a relative increase

A library grows from 800 books to 920 books. What is the percent increase?

  1. The increase is 920 − 800 = 120 books.
  2. Divide by the original 800: 120/800 = 0.15.
  3. Convert to percent: 15%.

Answer 15%

04 / UNDERSTAND & APPLY

Successive changes multiply

Each percentage in a sequence generally applies to the current amount, so multiply the factors. A rise of 20% followed by a fall of 20% gives 1.20 × 0.80 = 0.96 of the original, a net 4% decrease. Equal percentage increases and decreases do not cancel because their bases differ.

ORIGINAL WORKED EXAMPLE

Discount followed by tax

A $150 item is discounted by 20%. A 7% sales tax is then applied to the discounted price. What is the total?

  1. Discounted price is 150 × 0.80 = $120.
  2. Taxed total is 120 × 1.07 = $128.40.
  3. The combined multiplier is 0.80 × 1.07 = 0.856, not 1 − 0.20 + 0.07.

Answer $128.40

05 / UNDERSTAND & APPLY

Reverse a multiplier by division

If final = factor × original, then original = final/factor. Do not “undo” a 25% discount by adding 25% of the sale price: the sale price is a smaller base. A decrease of 25% retains 75%, so divide by 0.75.

ORIGINAL WORKED EXAMPLE

Find a pre-discount price

A jacket costs $84 after a 30% discount. What was its original price?

  1. Let P be the original price. The sale retains 70%, so 0.70P = 84.
  2. Divide by 0.70: P = 120.
  3. A 30% discount on $120 is $36, leaving $84.

Answer $120

06 / UNDERSTAND & APPLY

More than 100% is legitimate

If A is 160% of B, then A = 1.60B. If A is 160% greater than B, then A = 2.60B because the original 100% is still present. “Of” and “greater than” determine different multipliers. A quantity that is 250% of its original value has increased by 150%.

ORIGINAL WORKED EXAMPLE

Of versus greater than

A new battery capacity is 175% of the old capacity of 48 units. What is the new capacity, and its percent increase?

  1. 175% of 48 means 1.75 × 48 = 84.
  2. The increase is 84 − 48 = 36.
  3. Relative to the original, 36/48 = 0.75, so the increase is 75%.

Answer 84 units; 75% increase

07 / UNDERSTAND & APPLY

Rates can change in two ways

A rate moving from 24% to 30% rises by 6 percentage points. Its relative percent increase is (30 − 24)/24 × 100% = 25%. Percentage points subtract rates as displayed; percent change compares the difference to the old rate. Use the requested measure.

A statement such as “support doubled” means a 100% relative increase in the support measure, not necessarily an increase of 100 percentage points.

08 / UNDERSTAND & APPLY

Interest depends on the stated model

For simple interest, interest earned is Prt and total is P(1 + rt), where P is principal, r the rate per time unit and t the matching number of time units. For annual compounding, the simplified total is P(1 + r)^t for t years. Fees, different compounding intervals and payments need separate information. These are mathematical models, not a prediction of an actual account.

For P = 500 and r = 0.04 over 3 years, simple interest gives 500(1 + 0.12) = 560. Annual compounding gives 500(1.04)³ = 562.432 before any specified rounding. The models differ because compound interest changes the base each year.

09 / UNDERSTAND & APPLY

Original practice: say what the base is

Use the exact assumptions in each question.

ORIGINAL PRACTICE · 1

What is 18% of 250?

Reveal answer & reasoning

45

0.18 × 250 = 45.

ORIGINAL PRACTICE · 2

42 is what percent of 120?

Reveal answer & reasoning

35%

42/120 = 0.35, or 35 per hundred.

ORIGINAL PRACTICE · 3

A value of 75 increases by 12%. Find the result.

Reveal answer & reasoning

84

Multiply by 1.12: 75 × 1.12 = 84.

ORIGINAL PRACTICE · 4

A $240 item is discounted 15%. Find the sale price.

Reveal answer & reasoning

$204

The retained multiplier is 0.85, giving 240 × 0.85.

ORIGINAL PRACTICE · 5

A price after an 8% increase is $108. Find the old price.

Reveal answer & reasoning

$100

Solve 1.08P = 108, so P = 100.

ORIGINAL PRACTICE · 6

A quantity rises 10% and then falls 10%. What is the net change?

Reveal answer & reasoning

1% decrease

1.10 × 0.90 = 0.99, leaving 99% of the original.

ORIGINAL PRACTICE · 7

A is 220% greater than B. Write A in terms of B.

Reveal answer & reasoning

A = 3.20B

Add the original 100% to the extra 220%, giving 320% of B.

ORIGINAL PRACTICE · 8

A rate rises from 40% to 50%. Give both changes.

Reveal answer & reasoning

10 percentage points; 25% relative increase

Subtract to get 10 points; divide 10 by the old rate 40 to get 0.25.

ORIGINAL PRACTICE · 9

Find simple interest on $900 at 5% per year for 2 years.

Reveal answer & reasoning

$90 interest

Prt = 900 × 0.05 × 2 = 90; the total including principal would be $990.

KEEP THE BIG IDEAS

Quick revision

  • Every percentage has a reference base.
  • Multiply successive factors and divide to reverse a known change.
  • Percentage points, percent change, “of” and “greater than” are distinct.
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