ORIGINAL WORKED EXAMPLE
Slope between unequal steps
Find the slope through (−1,8) and (3,2).
- The horizontal change is 3 − (−1) = 4.
- The vertical change is 2 − 8 = −6.
- Divide changes: m = −6/4 = −3/2.
Answer −3/2
SAT · Algebra · TOPIC LESSON
Read a line as all ordered pairs satisfying one relationship.
BY THE END, YOU CAN
BEFORE YOU START
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LEARN THROUGH ORIGINAL PRACTICE
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01 / UNDERSTAND & APPLY
A linear equation in two variables usually gives infinitely many ordered-pair solutions. In Ax + By = C, A and B are not both zero. An ordered pair (p,q) lies on its graph exactly when Ap + Bq = C. One equation does not normally determine both coordinates uniquely.
Coordinates have an order: substitute the first value for x and the second for y. In an application, a point may satisfy the algebraic equation but be excluded because a count cannot be negative or fractional.
02 / UNDERSTAND & APPLY
Slope m = (y₂ − y₁)/(x₂ − x₁), provided x₂ ≠ x₁. Use the same subtraction order in numerator and denominator. Its units are y-units per x-unit. A negative slope means y decreases as x increases; it does not mean all y-values are negative.
ORIGINAL WORKED EXAMPLE
Find the slope through (−1,8) and (3,2).
Answer −3/2
03 / UNDERSTAND & APPLY
Slope-intercept form y = mx + b exposes slope m and y-intercept b. Point-slope form y − y₀ = m(x − x₀) uses one known point. Standard form Ax + By = C often arises naturally from totals. Equivalent equations can be multiplied by any nonzero constant.
When B ≠ 0, rearranging standard form gives y = (−A/B)x + C/B. Thus the coefficient A alone is not the slope.
ORIGINAL WORKED EXAMPLE
Find an equation of the line with slope 3 through (2,−1).
Answer y = 3x − 7
04 / UNDERSTAND & APPLY
At an x-intercept, y = 0; at a y-intercept, x = 0. An intercept is a point, although a problem may ask only for its nonzero coordinate. An axis crossing can have contextual meaning only when zero input or zero output is meaningful.
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ORIGINAL WORKED EXAMPLE
A workshop has 24 hours. Each large item needs 4 hours and each small item needs 3 hours. For 4x + 3y = 24, interpret both intercepts.
Answer (6,0) and (0,8)
05 / UNDERSTAND & APPLY
Distinct nonvertical parallel lines have equal slopes and different y-intercepts. Nonvertical perpendicular lines with defined, nonzero slopes satisfy m₁m₂ = −1. A vertical line is perpendicular to a horizontal line; that case is better recognized geometrically than forced into a slope formula.
Equal slopes and equal intercepts describe the same line, not two distinct parallel lines.
ORIGINAL WORKED EXAMPLE
Find the line through (4,1) perpendicular to y = 2x + 5.
Answer y = −x/2 + 3
06 / UNDERSTAND & APPLY
The equation y = k is horizontal: all x-values are allowed and the slope is zero. The equation x = h is vertical: x is fixed and the slope is undefined because the horizontal change is zero. A vertical line cannot be written as y = mx + b with a real slope.
ORIGINAL WORKED EXAMPLE
What is the line through (−3,2) and (−3,7)?
Answer x = −3
07 / UNDERSTAND & APPLY
In y = 84 − 6x, if y is liters remaining after x minutes, the initial amount is 84 liters and the rate is −6 liters per minute. The x-intercept is 14 minutes, but after that the model predicts negative volume and must stop. A mathematical line extends forever; a contextual model need not.
To convert a per-minute slope to a per-hour slope, multiply by 60 because an hour contains 60 minutes. Changing units changes the numerical slope without changing the underlying relationship.
08 / UNDERSTAND & APPLY
For the workshop equation 4x + 3y = 24, the table of pairs (0,8), (3,4), (6,0) describes three possible complete uses of the time. Substituting x = 3 gives 12 + 3y = 24, hence y = 4. The term 4x is hours spent on large items, not the number of large items.
To recover an equation from a linear table, find the slope from any two distinct x-values, use one point to find b, and check the remaining rows. For example, pairs (1,7), (3,3), (4,1) give slope −2 and y = −2x + 9. Graph these points and draw the line only when a continuous linear relationship is intended. Integer production counts are isolated feasible points on the line.
09 / UNDERSTAND & APPLY
Substitute a known point and compare the slope to verify an equation. A calculator graph helps connect forms, but visual steepness depends on axis scale. Read the labeled changes rather than estimating an angle from a stretched graph. Intercepts may lie outside the visible window.
Common errors: reversing only one subtraction, confusing x- and y-intercepts, treating A in Ax + By = C as the slope, and using a positive reciprocal rather than a negative reciprocal.
10 / UNDERSTAND & APPLY
All coordinates below use ordinary Cartesian axes.
ORIGINAL PRACTICE · 1
Yes
2(3) + 5(2) = 6 + 10 = 16.
ORIGINAL PRACTICE · 2
−3/2
Solving for y gives y = −(3/2)x + 5.
ORIGINAL PRACTICE · 3
(0,6)
Expand to y = 2x + 6, then set x = 0.
ORIGINAL PRACTICE · 4
(4,0)
At an x-intercept y = 0, so 5x = 20.
ORIGINAL PRACTICE · 5
y = −4x − 2
Parallel distinct lines share slope −4; the supplied point gives intercept −2.
ORIGINAL PRACTICE · 6
1/3
The product (−3)(1/3) is −1.
ORIGINAL PRACTICE · 7
0
All y-values are equal, so the vertical change is zero for every nonzero horizontal change.
ORIGINAL PRACTICE · 8
30 minutes; 0 ≤ t ≤ 30
Set L = 0 to obtain t = 30. The physical model starts at t = 0 and cannot represent negative remaining volume.
KEEP THE BIG IDEAS
READ WITH CONTEXT
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