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SAT · Algebra · TOPIC LESSON

Linear equations in two variables

Read a line as all ordered pairs satisfying one relationship.

SAT35 min study guide10 indexed sections

BY THE END, YOU CAN

  • Translate among standard, slope-intercept and point-slope forms.
  • Calculate slope and intercepts and interpret their units.
  • Recognize parallel, perpendicular, horizontal and vertical lines.

BEFORE YOU START

  • One-variable equation solving.
  • Ordered pairs and coordinate axes.

Original educational lesson. Work through the examples before revealing the practice answers. This lesson supports SAT Math and Reading and Writing skill study; it does not reproduce official questions or guarantee a score.

LEARN THROUGH ORIGINAL PRACTICE

Original SAT-style worked examples and practice

The teaching passages, worked examples and exercises in this lesson are original. They are not official College Board questions or past-exam reproductions. Blueprint and observed-practice analytics describe separate factual metadata; those source questions are not displayed here.

01 / UNDERSTAND & APPLY

An equation describes many pairs

A linear equation in two variables usually gives infinitely many ordered-pair solutions. In Ax + By = C, A and B are not both zero. An ordered pair (p,q) lies on its graph exactly when Ap + Bq = C. One equation does not normally determine both coordinates uniquely.

Coordinates have an order: substitute the first value for x and the second for y. In an application, a point may satisfy the algebraic equation but be excluded because a count cannot be negative or fractional.

02 / UNDERSTAND & APPLY

Slope measures change, not height

Slope m = (y₂ − y₁)/(x₂ − x₁), provided x₂ ≠ x₁. Use the same subtraction order in numerator and denominator. Its units are y-units per x-unit. A negative slope means y decreases as x increases; it does not mean all y-values are negative.

ORIGINAL WORKED EXAMPLE

Slope between unequal steps

Find the slope through (−1,8) and (3,2).

  1. The horizontal change is 3 − (−1) = 4.
  2. The vertical change is 2 − 8 = −6.
  3. Divide changes: m = −6/4 = −3/2.

Answer −3/2

03 / UNDERSTAND & APPLY

Choose the form that exposes the information

Slope-intercept form y = mx + b exposes slope m and y-intercept b. Point-slope form y − y₀ = m(x − x₀) uses one known point. Standard form Ax + By = C often arises naturally from totals. Equivalent equations can be multiplied by any nonzero constant.

When B ≠ 0, rearranging standard form gives y = (−A/B)x + C/B. Thus the coefficient A alone is not the slope.

ORIGINAL WORKED EXAMPLE

Build a line from a point and slope

Find an equation of the line with slope 3 through (2,−1).

  1. Use point-slope form: y − (−1) = 3(x − 2).
  2. Distribute: y + 1 = 3x − 6.
  3. Subtract 1: y = 3x − 7.
  4. Check the point: 3(2) − 7 = −1.

Answer y = 3x − 7

04 / UNDERSTAND & APPLY

Intercepts are zero-coordinate cases

At an x-intercept, y = 0; at a y-intercept, x = 0. An intercept is a point, although a problem may ask only for its nonzero coordinate. An axis crossing can have contextual meaning only when zero input or zero output is meaningful.

Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.

A line as a set of ordered-pair solutionsA line as a set of ordered-pair solutions. Axes marked every two units; line and point labels give exact values.xy-2-222446688(0,6)(2,4)(6,0)y = −x + 6x + y = 6rise/run = −2/2 = −1
The line y = −x + 6 contains (0,6), (2,4) and (6,0); both axes use the same unit scale.

ORIGINAL WORKED EXAMPLE

A resource constraint

A workshop has 24 hours. Each large item needs 4 hours and each small item needs 3 hours. For 4x + 3y = 24, interpret both intercepts.

  1. Set y = 0: 4x = 24, so the x-intercept is (6,0).
  2. Set x = 0: 3y = 24, so the y-intercept is (0,8).
  3. The workshop can make 6 large items and no small items, or 8 small items and no large items, using all 24 hours.

Answer (6,0) and (0,8)

05 / UNDERSTAND & APPLY

Direction relationships

Distinct nonvertical parallel lines have equal slopes and different y-intercepts. Nonvertical perpendicular lines with defined, nonzero slopes satisfy m₁m₂ = −1. A vertical line is perpendicular to a horizontal line; that case is better recognized geometrically than forced into a slope formula.

Equal slopes and equal intercepts describe the same line, not two distinct parallel lines.

ORIGINAL WORKED EXAMPLE

A perpendicular line

Find the line through (4,1) perpendicular to y = 2x + 5.

  1. The given slope is 2. The perpendicular slope is −1/2 because 2(−1/2) = −1.
  2. Use the point: y − 1 = −(1/2)(x − 4).
  3. Simplify: y = −x/2 + 3.

Answer y = −x/2 + 3

06 / UNDERSTAND & APPLY

Vertical and horizontal are different

The equation y = k is horizontal: all x-values are allowed and the slope is zero. The equation x = h is vertical: x is fixed and the slope is undefined because the horizontal change is zero. A vertical line cannot be written as y = mx + b with a real slope.

ORIGINAL WORKED EXAMPLE

A zero denominator is information

What is the line through (−3,2) and (−3,7)?

  1. Both points have x = −3, while y changes.
  2. The slope ratio is (7 − 2)/(−3 − (−3)) = 5/0, which is undefined.
  3. The equation is x = −3, not y = −3.

Answer x = −3

07 / UNDERSTAND & APPLY

Coefficients in a real model

In y = 84 − 6x, if y is liters remaining after x minutes, the initial amount is 84 liters and the rate is −6 liters per minute. The x-intercept is 14 minutes, but after that the model predicts negative volume and must stop. A mathematical line extends forever; a contextual model need not.

To convert a per-minute slope to a per-hour slope, multiply by 60 because an hour contains 60 minutes. Changing units changes the numerical slope without changing the underlying relationship.

08 / UNDERSTAND & APPLY

A table, an equation and a constraint

For the workshop equation 4x + 3y = 24, the table of pairs (0,8), (3,4), (6,0) describes three possible complete uses of the time. Substituting x = 3 gives 12 + 3y = 24, hence y = 4. The term 4x is hours spent on large items, not the number of large items.

To recover an equation from a linear table, find the slope from any two distinct x-values, use one point to find b, and check the remaining rows. For example, pairs (1,7), (3,3), (4,1) give slope −2 and y = −2x + 9. Graph these points and draw the line only when a continuous linear relationship is intended. Integer production counts are isolated feasible points on the line.

09 / UNDERSTAND & APPLY

Check more than appearance

Substitute a known point and compare the slope to verify an equation. A calculator graph helps connect forms, but visual steepness depends on axis scale. Read the labeled changes rather than estimating an angle from a stretched graph. Intercepts may lie outside the visible window.

Common errors: reversing only one subtraction, confusing x- and y-intercepts, treating A in Ax + By = C as the slope, and using a positive reciprocal rather than a negative reciprocal.

10 / UNDERSTAND & APPLY

Original practice: connect equations and graphs

All coordinates below use ordinary Cartesian axes.

ORIGINAL PRACTICE · 1

Does (3,2) lie on 2x + 5y = 16?

Reveal answer & reasoning

Yes

2(3) + 5(2) = 6 + 10 = 16.

ORIGINAL PRACTICE · 2

Find the slope of 3x + 2y = 10.

Reveal answer & reasoning

−3/2

Solving for y gives y = −(3/2)x + 5.

ORIGINAL PRACTICE · 3

Find the y-intercept of y − 4 = 2(x + 1).

Reveal answer & reasoning

(0,6)

Expand to y = 2x + 6, then set x = 0.

ORIGINAL PRACTICE · 4

Find the x-intercept of 5x − 2y = 20.

Reveal answer & reasoning

(4,0)

At an x-intercept y = 0, so 5x = 20.

ORIGINAL PRACTICE · 5

Which line through (0,−2) is parallel to y = −4x + 7?

Reveal answer & reasoning

y = −4x − 2

Parallel distinct lines share slope −4; the supplied point gives intercept −2.

ORIGINAL PRACTICE · 6

What is the slope of a line perpendicular to y = −3x + 8?

Reveal answer & reasoning

1/3

The product (−3)(1/3) is −1.

ORIGINAL PRACTICE · 7

What is the slope of y = 9?

Reveal answer & reasoning

0

All y-values are equal, so the vertical change is zero for every nonzero horizontal change.

ORIGINAL PRACTICE · 8

A tank model is L = 150 − 5t with t in minutes. When is the tank empty, and what is the valid time interval?

Reveal answer & reasoning

30 minutes; 0 ≤ t ≤ 30

Set L = 0 to obtain t = 30. The physical model starts at t = 0 and cannot represent negative remaining volume.

KEEP THE BIG IDEAS

Quick revision

  • Slope is a ratio of coordinate changes with units.
  • Set the other coordinate to zero to find an intercept.
  • Vertical lines have undefined slope; perpendicular axis-parallel lines need separate treatment.
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