ORIGINAL WORKED EXAMPLE
Substitute an expression
For f(x) = 4x − 7, simplify f(t + 2) − f(t).
- f(t + 2) = 4(t + 2) − 7 = 4t + 1.
- f(t) = 4t − 7.
- Subtract the complete second expression: (4t + 1) − (4t − 7) = 8.
Answer 8
SAT · Algebra · TOPIC LESSON
Connect constant rate of change with function notation, tables and contextual models.
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BEFORE YOU START
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LEARN THROUGH ORIGINAL PRACTICE
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01 / UNDERSTAND & APPLY
A function is a rule that gives exactly one output for each input in its domain. The notation f(3) means the output when the input is 3, not f multiplied by 3. A linear function has the form f(x) = mx + b; its graph is a nonvertical line. A vertical line is not a function of x because the same x would have multiple outputs.
The number m is the constant rate of change and b = f(0) is the output at zero input. A constant function, m = 0, is included here.
02 / UNDERSTAND & APPLY
To evaluate f(a + h), replace every x in the rule by the whole expression a + h. The output difference f(a + h) − f(a) equals mh for a linear function. Dividing by a nonzero input change h gives the same slope every time.
ORIGINAL WORKED EXAMPLE
For f(x) = 4x − 7, simplify f(t + 2) − f(t).
Answer 8
03 / UNDERSTAND & APPLY
A table is consistent with a linear model when every ratio Δoutput/Δinput is equal. Equal output differences are evidence only if the input gaps are equal. A finite table can be fit by other rules; a question must state or justify using a linear model.
ORIGINAL WORKED EXAMPLE
A linear function has f(1) = 9 and f(5) = 21. Find f(8).
Answer 30
04 / UNDERSTAND & APPLY
The y-intercept is (0,f(0)); a zero is an input where f(x) = 0. For f(x) = mx + b with m ≠ 0, the zero is −b/m. Do not confuse the zero input with the output zero. The sign of m determines whether the function is increasing or decreasing.
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ORIGINAL WORKED EXAMPLE
A candle has height H(t) = 18 − 0.6t centimeters after t hours. Find and interpret H(5) and its zero.
Answer H(5) = 15 cm; zero at t = 30 hours
05 / UNDERSTAND & APPLY
Build a model using output = initial output + rate × elapsed input. The starting observation may occur at a nonzero input, so it need not be the intercept. Use f(x) = f(a) + m(x − a) when an observed point is easier than the value at zero.
ORIGINAL WORKED EXAMPLE
At mile marker 12, a road is 340 meters above sea level. Its elevation rises at a constant 5 meters per mile. Give E(x), with x the mile marker.
Answer E(x) = 5x + 280
06 / UNDERSTAND & APPLY
Adding k outside f shifts every output by k: g(x) = f(x) + k. Replacing x with x − h shifts the graph right by h: g(x) = f(x − h). With a linear rule these can look alike after simplification, so do the substitution before describing coefficients. Multiplying f(x) by c multiplies both slope and intercept by c.
ORIGINAL WORKED EXAMPLE
Let f(x) = 2x + 3 and g(x) = f(x − 4). Find g(0) and the slope of g.
Answer g(0) = −5; slope 2
07 / UNDERSTAND & APPLY
A larger starting value does not guarantee a larger output for all inputs. Two linear cost functions with different slopes may intersect. Solve equality to find the crossover, then use the slope or a test input to determine which model is larger on each side. If the domain is whole numbers, evaluate nearby integers.
The average rate of change between any two distinct inputs is m. An average of two output values, by contrast, is an output statistic and generally is not the slope.
08 / UNDERSTAND & APPLY
An output request evaluates the rule; an input request solves an equation. If C(t) = 28 + 6t dollars for t hours, C(t) = 70 gives 6t = 42, so t = 7 hours. The point (7,70) lies on the cost graph and says the same thing.
A constant function f(x) = 9 has no input producing output 10 and every allowed input producing output 9. Thus “find the input” does not always have exactly one answer. A linear rule with nonzero slope has one algebraic input for a given output, but that input must still lie in its context domain.
09 / UNDERSTAND & APPLY
A calculator table can verify several input/output pairs or locate where a function changes sign. For an exact crossover or intercept, solve algebraically and substitute. Label axes with the actual variables and units; a graph that silently swaps input and output changes the meaning.
Avoid reading f(a) as an input, assuming every increase is a percent increase, or taking an output difference without dividing by its input gap.
10 / UNDERSTAND & APPLY
Work with the stated linear models.
ORIGINAL PRACTICE · 1
14
Substitute −2: −3(−2) + 8 = 6 + 8 = 14.
ORIGINAL PRACTICE · 2
21
An input increase of 3 changes the output by slope × change = 7 × 3.
ORIGINAL PRACTICE · 3
f(x) = 2x + 1
Slope is 8/4 = 2; 5 = 2(2) + b gives b = 1.
ORIGINAL PRACTICE · 4
x = 3
Set the output equal to zero: 15 − 5x = 0.
ORIGINAL PRACTICE · 5
Yes
The successive slopes are 4/2 = 2 and 6/3 = 2; all three lie on y = 2x + 1.
ORIGINAL PRACTICE · 6
10
Adding 6 to the output gives g(x) = −2x + 10.
ORIGINAL PRACTICE · 7
n = 4
20 + 4n = 8 + 7n gives 12 = 3n. Both cost $36 at n = 4.
ORIGINAL PRACTICE · 8
P(t) = 35 + 12t; P(0) = 35 parts
The rate multiplies elapsed minutes; the existing parts are the starting output, added once.
KEEP THE BIG IDEAS
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