Applying Data Sufficiency to quantitative relationships
Translate rates, ratios, averages and integer facts into precise sufficiency tests.
GMAT35 min study guide8 indexed sections
BY THE END, YOU CAN
Explain ratios and unknown scale
Explain percent bases
Explain rate and unit dependencies
Explain averages and counts
Explain ranges and inequalities
Explain divisibility and parity
Explain logical dependency diagrams
Explain deciding when information is enough
BEFORE YOU START
Five-case Data Sufficiency logic
Ratios, percentages, mean and elementary number properties
Original educational lesson. Work through the examples before revealing the practice answers. This original lesson supports current GMAT study through an editorial skill map. It does not reproduce official questions, predict exam content or guarantee a score.
LEARN THROUGH ORIGINAL PRACTICE
Original GMAT-style worked examples and practice
All passages, examples and exercises here are original. No official GMAC questions, choices or explanations are reproduced. This independent preparation resource is not affiliated with or endorsed by GMAC. GMAT is a trademark of the Graduate Management Admission Council.
01 / UNDERSTAND & APPLY
A ratio needs a scale only for a count
For every Data Sufficiency exercise here select exactly one case: A = statement 1 alone suffices, statement 2 alone does not; B = statement 2 alone suffices, statement 1 alone does not; C = together sufficient but neither alone; D = each alone sufficient; E = insufficient even together. Assume all stated conditions are consistent. Test each statement with the stem, never with the other statement smuggled in.
A ratio a:b=3:5 can be represented as a=3k and b=5k. It determines a/b and a/(a+b), but not a, b or a+b unless another fact fixes k. The target tells you whether the scale is actually needed.
ORIGINAL WORKED EXAMPLE
Unknown scale becomes known
How many red counters are in a box containing only red and blue counters? (1) Red:blue=3:5. (2) There are 40 counters.
Statement 1 permits 3 red with 5 blue or 6 red with 10 blue.
Statement 2 permits several color splits totaling 40.
Together 8k=40, so k=5 and red=15.
Answer C
ORIGINAL PRACTICE · 1
What fraction of the counters are red if all are red or blue? (1) Red:blue=3:5. (2) There are 80 counters.
Reveal answer & reasoning
A
The ratio alone fixes red fraction 3/(3+5)=3/8. The total count alone does not fix the color split.
02 / UNDERSTAND & APPLY
Percentages require a named base
A percent is a relationship, not a standalone amount. “Profit is 20%” needs a base such as cost or revenue. If profit is 20% of cost C, revenue is 1.2C; if profit is 20% of revenue R, cost is 0.8R.
Successive percent changes multiply scale factors. An increase followed by an equal-percent decrease generally does not restore the original value because the second base changes.
ORIGINAL WORKED EXAMPLE
Margin and amount
What is the selling price of one item? (1) Profit is 25% of its $80 cost. (2) Profit is $20.
Statement 1 contains both a base and rate: profit=0.25×80=20 and price=100.
Statement 2 alone gives profit but no cost, allowing costs 60 or 80 and prices 80 or 100.
Only statement 1 fixes price.
Answer A
ORIGINAL PRACTICE · 1
What was last year’s revenue? (1) This year’s revenue is 120% of last year’s. (2) The increase is $30,000.
Reveal answer & reasoning
C
The relative change alone lacks scale; the increase alone lacks a rate. Together 0.20×old=30,000, so old=$150,000.
03 / UNDERSTAND & APPLY
Rates need compatible units and the right dependency
Distance=speed×time assumes the stated speed applies for that travel interval. Work=rate×time needs operating time, not merely calendar span. A rate expressed per minute must be converted before multiplying by hours.
The dependency diagram makes missing inputs visible: knowing any two appropriate quantities may fix the third, but only when the model itself is justified. Average speed is total distance divided by total time, not usually the mean of segment speeds.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
Original schematic. The constant-rate assumption and positive denominators are required.
ORIGINAL WORKED EXAMPLE
Hours versus shifts
How many units did a press produce at its constant operating rate? (1) Its rate was 18 units per minute. (2) It ran for exactly 2 hours.
Statement 1 lacks time; statement 2 lacks rate.
Together operating time is 120 minutes.
Output=18×120=2,160 units. The unit conversion is part of the model.
Answer C
ORIGINAL PRACTICE · 1
How long did a cyclist ride at a constant speed, completing an entire route? (1) The completed route was 42 km and speed was 14 km/h. (2) The cyclist left at 9 a.m.
Reveal answer & reasoning
A
Statement 1 fixes time=42/14=3 hours. A departure clock time alone does not establish duration.
04 / UNDERSTAND & APPLY
A mean hides both a total and a count
Mean=total/count. A mean and count fix a total; a total and mean can fix count if the mean is nonzero. When combining groups, weight group means by counts unless equal group sizes are known.
The target might be an overall mean, a missing individual value or a count. Information sufficient for one is not automatically sufficient for another. A group mean says little about the spread or any particular member.
ORIGINAL WORKED EXAMPLE
Two means without group sizes
What is the combined average of groups P and Q? (1) Their means are 10 and 20. (2) They have the same positive number of observations.
Statement 2 alone specifies equal weights but not either mean.
Together the equal-size weighted mean is (10+20)/2=15.
Answer C
ORIGINAL PRACTICE · 1
What is the total of 8 numbers? (1) Their mean is 12. (2) Their median is 12.
Reveal answer & reasoning
A
Mean and count fix total 96. Median does not: eight 12s total 96; replacing the largest by 20 preserves median 12 but raises the total.
05 / UNDERSTAND & APPLY
Use inequalities to settle the requested comparison
An interval can establish a proposition even when it does not identify a value. To compare sums, combine valid lower or upper bounds. For products, first resolve signs: multiplying two negative lower bounds as though all quantities were positive can reverse conclusions.
Bounds must retain strictness. If x≥3 and y≥4, x+y≥7; this proves x+y>6 but does not prove x+y>7.
ORIGINAL WORKED EXAMPLE
Separate lower bounds
Is a+b>10? (1) a>6. (2) b>4.
With statement 1 only, a=7 and b=0 gives no; a=7 and b=5 gives yes.
With statement 2 only, b=5 and a=0 gives no; b=5 and a=7 gives yes.
Together a+b>6+4=10, so yes is guaranteed.
Answer C
ORIGINAL PRACTICE · 1
Is x²<16? (1) −3<x<3. (2) x<4.
Reveal answer & reasoning
A
Statement 1 gives |x|<3 and x²<9<16. Statement 2 permits x=0 and x=−5, producing yes and no.
06 / UNDERSTAND & APPLY
Divisibility and parity can settle a target cheaply
For an integer, even means divisible by 2; odd means one more than an even integer. A multiple of 12 must be divisible by 3 and 4, but a multiple of 3 alone need not be even. Counterexamples are often faster than extensive factorization.
Use the least common multiple when combining divisibility constraints. Do not multiply divisors unless their common factors have been handled. Divisibility by 4 and 6 together implies divisibility by 12, not necessarily 24.
ORIGINAL PRACTICE · 1
Is positive integer n divisible by 12? (1) n is divisible by 4. (2) n is divisible by 6.
Reveal answer & reasoning
C
Statement 1 allows 4 (no) and 12 (yes). Statement 2 allows 6 (no) and 12 (yes). Together n is a multiple of lcm(4,6)=12.
ORIGINAL PRACTICE · 2
Is integer n odd? (1) n² is odd. (2) n+1 is even.
Reveal answer & reasoning
D
An even n has an even square, so statement 1 forces odd n. Statement 2 directly makes n one less than an even integer, also odd.
07 / UNDERSTAND & APPLY
Ask which missing quantity actually matters
List the model inputs, mark which are fixed and look for cancellation before requesting more data. To find profit per item you may need revenue and cost per item; to find profit margin you need the correct revenue denominator as well.
A dependency map is a thinking aid rather than a guarantee. For example, total cost may include a fixed fee in addition to a per-unit charge, so dividing cost by units does not necessarily recover the variable price.
ORIGINAL PRACTICE · 1
What is average delivery cost per package, given total cost in dollars = F+vn for n packages, where F is a fixed fee in dollars and v is dollars per package? (1) F=40 and v=3. (2) n=20.
Reveal answer & reasoning
C
The target is F/n+v. Statement 1 leaves n unknown; statement 2 leaves F and v unknown. Together average cost=40/20+3=$5 per package.
08 / UNDERSTAND & APPLY
Stop at a uniquely defined target
Many DI questions reward deciding that a calculation is possible, not doing it. If all inputs and the model are fixed, a complicated quotient can still be sufficient. If a free parameter remains, check whether changing it changes the target rather than automatically declaring failure.
After a sufficiency result, inspect domains and units once more. Counts must be feasible integers, time nonnegative, and division valid. A superficially unique algebraic answer outside the domain does not establish a legitimate scenario.
KEEP THE BIG IDEAS
Quick revision
Ratios fix proportions without fixing counts.
State the base of every percentage.
Rate models require compatible units and justified assumptions.
Use counts to weight means and domains to test inequalities.
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