Track the carbon attached to metal through proton transfer, carbonyl addition, homologation and selective coupling.
JEE Main · JEE Advanced · NEET UG43 min study guide10 indexed sections
BY THE END, YOU CAN
Explain carbon–metal bond polarity without treating every reagent as a free carbanion.
Check acidic-proton and electrophile compatibility before predicting a sequence.
Map carbonyl, ester, nitrile, CO₂ and epoxide carbons into products.
Distinguish organomagnesium, organolithium and organocopper reaction tendencies.
Design original retrosynthetic disconnections with carbon-count checks.
Separate reaction stage from protonating or hydrolytic workup.
BEFORE YOU START
Carbonyl addition and acyl substitution.
Acid–base chemistry and functional groups.
Condensed structures, carbon counting and basic retrosynthesis.
Original educational lesson. Work through the examples before revealing the practice answers. Check the current official syllabus separately; historical question frequency does not establish eligibility or predict future questions.
CONNECT THE CONCEPT TO THE EXAM
Selected exam questions & worked solutions
These selected examples are separate from the original practice below. Each identifies its exam, year and wording. They do not represent every paper or every selected year.
No source-verified exam questions have been published for this lesson yet. The worked examples and practice below are original teaching material, not past-exam questions.
01 / UNDERSTAND & APPLY
1. The carbon–metal bond changes carbon’s reactive role
An organometallic compound contains a direct carbon–metal bond in the usual structural definition. In a Grignard reagent RMgX, the carbon attached to magnesium has substantial nucleophilic and basic character because the bond is polarized toward carbon. The group R is transferred or protonated through that carbon, not through the halogen.
The notation R⁻ is a useful electron-bookkeeping shorthand for many reaction predictions, but a solution of RMgX is not simply a bottle of isolated free carbanions and bare Mg²⁺. Solvent coordination, aggregation and equilibria between organomagnesium species affect real reactivity. Use the shorthand to track bonds while respecting its limits.
Organolithium reagents likewise have strongly basic, nucleophilic carbon character and can be highly reactive. Organocopper reagents often have different selectivity and lower basicity in useful comparisons. All carbon–metal reagents cannot be substituted for one another in a reaction map without checking the actual transformation.
A Grignard reagent can be represented conceptually as arising from a suitable organic halide and magnesium in a compatible ether-type medium. Alkyl, aryl and vinyl groups can participate in appropriate preparations. The medium must not consume the strongly basic reagent, and actual formation may be complicated by competing reactions.
This lesson is a reaction-planning and atom-mapping treatment. These reagents can be moisture-sensitive, air-sensitive or pyrophoric, and their preparation and workup require approved laboratory procedures. The reaction labels describe conceptual transformations, not an operational synthesis protocol.
02 / UNDERSTAND & APPLY
2. Acidic protons can consume the reagent before carbon–carbon bond formation
Water, alcohols, phenols, carboxylic acids and many N–H-containing groups can protonate a strongly basic organomagnesium or organolithium carbon. The organic group then becomes RH rather than adding to the intended electrophile. A molecule with a carbonyl and an unprotected OH cannot be treated as a simple carbonyl-only substrate.
The acid–base comparison is governed by relative conjugate-acid stabilities in the relevant medium. Ordinary hydrocarbon conjugate acids of Grignard reagents are very weak acids, so many common X–H groups are sufficiently acidic to quench them. Terminal alkynes can also undergo deprotonation rather than the hoped-for carbonyl addition.
A deuterated proton source can reveal the carbon that was bonded to metal: an idealized RMgX followed by D₂O gives R–D at that position. This labels the former carbon–metal site; it does not randomly exchange every hydrogen in R under the simplified reaction model.
The reaction stage and the workup stage must be separate in a sequence. Carbonyl addition first forms a metal alkoxide. A later compatible protonating workup gives the neutral alcohol. Putting aqueous acid into the initial reagent mixture would consume the organometallic reagent rather than preserve it for carbon attack.
Protecting an acidic group can make a route conceptually possible, but a protection plan must also survive the organometallic stage and be removable without damaging the target. Protecting-group names are not magic exceptions to compatibility. A free carbonyl elsewhere in a reagent precursor may also react before the intended intermolecular step.
ORIGINAL WORKED EXAMPLE
Identify the first event
A model substrate HOCH₂CH₂CHO is treated with one equivalent of a strongly basic methylmagnesium reagent. Why is simple quantitative methyl addition to CHO not a justified prediction?
The substrate contains an O–H proton as well as an aldehyde.
Acid–base consumption can use the reagent to form methane and a metal alkoxide.
The one-equivalent supply is therefore not automatically available for the aldehyde addition.
A viable route needs explicit handling of that acidic group and the required reagent stoichiometry.
Answer The free OH consumes organometallic basicity; unqualified one-equivalent carbonyl addition is not valid.
03 / UNDERSTAND & APPLY
3. Carbonyl addition joins the reagent carbon to the carbonyl carbon
In the simplified carbonyl-addition mechanism, the nucleophilic carbon of R–M forms a bond to the electrophilic carbonyl carbon. The C=O pi pair moves to oxygen, producing an alkoxide-containing intermediate. Workup protonates oxygen; it does not insert a new carbon into the skeleton.
Formaldehyde gives RCH₂OH after addition and workup: its carbon becomes the terminal CH₂OH carbon, so the product has one more carbon than R. An aldehyde R′CHO generally gives a secondary alcohol R′CH(OH)R. Formaldehyde is the important primary-alcohol exception to the broad aldehyde rule.
A ketone R′COR″ gives a tertiary alcohol R′C(OH)(R)R″ after ordinary carbon addition and workup. All three carbon substituents attached to the alcohol carbon can be traced: two came from the ketone, and one from the organometallic reagent.
A planar carbonyl can be attacked from either face. If a new stereocentre is formed from achiral reagents in an achiral environment with no other stereochemical control, a racemic product may result. Existing stereocentres or chiral catalysts can change facial selectivity; “Grignard always gives racemate” is too broad.
Count total carbons before naming the product. The carbonyl carbon is already part of the electrophile’s carbon count, while the transferred R group contributes its own carbon count. Magnesium and halogen do not become part of the ordinary alcohol skeleton.
ORIGINAL WORKED EXAMPLE
Map a seven-carbon tertiary alcohol
Predict the product connectivity from pentan-2-one and an ethylmagnesium reagent followed by protonating workup.
Pentan-2-one is CH₃COCH₂CH₂CH₃ and contains five carbons.
The incoming ethyl contributes two carbons.
The alcohol carbon bears methyl, ethyl and propyl substituents.
The longest chain through ethyl–carbinol–propyl has six carbons, with OH and methyl at C3.
Answer 3-Methylhexan-3-ol, a seven-carbon product.
04 / UNDERSTAND & APPLY
4. Esters usually consume two carbon-transfer equivalents
An ester R′COOR″ can first undergo nucleophilic addition to its carbonyl, followed by collapse of the tetrahedral intermediate and loss of the alkoxy group. This gives a ketone R′COR when the incoming organometallic group is R. That ketone is generally reactive toward a second addition.
The usual result with sufficient Grignard reagent is therefore R′C(OH)(R)₂ after workup. Two identical incoming R groups attach to the former ester carbonyl carbon. The original OR″ group leaves and ultimately appears in a separate alcohol-derived product rather than staying attached to the tertiary alcohol carbon.
One equivalent of Grignard reagent does not generally provide a clean universal method for stopping an ordinary ester at the ketone. As ketone forms, it can compete effectively for remaining reagent. A reagent or derivative designed for single addition is needed when selective ketone preparation is the goal.
Formate esters HCOOR″ are a special structural case. The original acyl substituent is H rather than a carbon group. After two identical R additions, the product is R₂CHOH, a secondary alcohol. Thus “all esters plus Grignard give tertiary alcohols” is an overgeneralization.
Acid chlorides can also overadd with strongly nucleophilic Grignard or organolithium reagents under ordinary conditions. An organocopper approach can often stop at a ketone for a suitable acyl chloride. The substrate class and reagent choice jointly determine whether one or two carbon additions occur.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
Net reaction-stage map, not full curved-arrow mechanisms. Metal coordination and counterions are omitted. Nitrile hydrolysis introduces oxygen from the aqueous workup while active organometallic reagent is quenched. Ester leaving-group carbons are tracked separately.
ORIGINAL WORKED EXAMPLE
Do not retain the ester ethoxy carbons in the main product
Ethyl propanoate reacts with sufficient methylmagnesium reagent and is then worked up. Identify the principal carbon-addition alcohol and account for the ester’s ethoxy group.
The acyl portion is CH₃CH₂CO–.
Two incoming methyl groups attach to its carbonyl carbon.
The main product is CH₃CH₂C(OH)(CH₃)₂.
The ethoxy group leaves during acyl substitution and gives ethanol after workup; its two carbons are not in the main alcohol.
Answer 2-Methylbutan-2-ol as the five-carbon addition product, with ethanol derived from the leaving ethoxy group.
05 / UNDERSTAND & APPLY
5. Nitriles give a ketone after hydrolytic workup
A nitrile R′C≡N has an electrophilic carbon. Addition of a suitable Grignard carbon gives a metal-bound imine-anion-type intermediate. Subsequent hydrolytic workup converts that C=N-derived unit into a carbonyl, giving ketone R′COR.
The nitrile carbon becomes the ketone carbonyl carbon. It is not lost with nitrogen. The incoming organometallic group and the original nitrile substituent occupy the two carbon sides of the product ketone. This is an effective place to use carbon labels in a sequence.
The ketone appears during workup, when active Grignard reagent is being destroyed by the aqueous medium. It is therefore not exposed in the same way to an excess of active reagent as the ketone intermediate in ester addition. This explains the different usual outcomes without claiming that ketones somehow cannot react with Grignard reagents.
The nitrile nitrogen is removed into nitrogen-containing workup products rather than remaining in the ketone. The oxygen in the ketone is supplied through hydrolysis, so an oxygen-label experiment depends on the workup water and any exchange. Do not draw an oxygen atom emerging from the nitrile reagent itself.
The route requires compatible other groups. A nitro group, acidic proton or additional reactive carbonyl may interfere with strongly reactive organometallic chemistry. A retrosynthetic disconnection is only a first step; a chemically compatible substrate must still be chosen.
ORIGINAL WORKED EXAMPLE
Choose a nitrile disconnection
Give a conceptual nitrile/Grignard pair for hexan-3-one, CH₃CH₂COCH₂CH₂CH₃, followed by hydrolysis.
The carbonyl carbon can come from a nitrile carbon.
Choose propanenitrile, CH₃CH₂CN, to supply the ethyl side plus the carbonyl carbon.
An n-propylmagnesium reagent supplies the propyl side.
Three nitrile carbons plus three transferred carbons give six total.
Answer Propanenitrile plus an n-propylmagnesium reagent, followed by hydrolytic workup. A complementary valid disconnection can interchange the two carbon sides.
06 / UNDERSTAND & APPLY
6. CO₂ adds one carbon; protonation adds none
An organomagnesium carbon can attack carbon dioxide to form a carboxylate-containing intermediate. Acidic workup gives RCO₂H. The CO₂ carbon is the new carboxyl carbon, so this is a one-carbon homologation relative to the original R group.
For example, a four-carbon alkyl group gives a five-carbon carboxylic acid if no rearrangement or other reaction occurs. An arylmagnesium group gives an aryl carboxylic acid with an added exocyclic carbon; the aromatic ring carbon count is unchanged.
If the CO₂ carbon is labelled ¹³C, that label appears at the carboxyl carbon. The oxygen atoms belong to the carboxylate-derived group and can be affected by exchange in subsequent chemistry. A carbon-label assignment is usually more robust than assuming oxygen labels never exchange during acidic workup.
In contrast, quenching RMgX with a proton source gives RH with no carbon addition, and quenching with a deuteron source gives RD. These three electrophiles, H⁺, D⁺ and CO₂, therefore give different atom-count signatures even though they react at the same organometallic carbon.
A carboxylic acid itself is not a simple substitute for CO₂ in this carbon-addition route. Its acidic proton consumes the reagent by acid–base reaction. The product after that initial encounter is a carboxylate salt and RH, not automatically the desired tertiary alcohol.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
Each panel is a separate reaction, not a downward multistep sequence. The ethyl fragment is retained, and the electrophile supplies the displayed additional carbon count. Compatible conditions and complete intended transformation are assumed.
ORIGINAL WORKED EXAMPLE
Trace a carbon isotope
An n-propylmagnesium reagent reacts with ¹³CO₂ and then undergoes protonating workup. Give the acid connectivity and isotope location.
The n-propyl group has three carbons.
CO₂ contributes one additional carbon.
The new acid is CH₃CH₂CH₂¹³CO₂H.
The label is the carboxyl carbon, not a terminal methyl carbon.
Answer Butanoic acid labelled at its carboxyl carbon.
07 / UNDERSTAND & APPLY
7. Epoxide opening retains the epoxide carbon skeleton
A strongly nucleophilic organometallic reagent can open a suitable epoxide by attack at a ring carbon with cleavage of that carbon’s bond to oxygen. Under the usual basic nucleophilic conditions, attack is favoured at the less hindered epoxide carbon and resembles backside substitution.
With ethylene oxide, the two ring carbons are equivalent. Adding R gives RCH₂CH₂O⁻ in the simplified alkoxide representation, then RCH₂CH₂OH after workup. This extends the R skeleton by two carbons, unlike formaldehyde’s one-carbon alcohol extension.
With an unsymmetrical epoxide, identify which carbon is attacked and which remains bonded to oxygen. The new C–C bond forms at the attacked carbon, while the eventual OH group is attached to the other original epoxide carbon. Merely adding “two carbons and OH at the end” is not sufficient for every substituted epoxide.
Backside attack gives inversion at a stereogenic attacked epoxide carbon in the standard mechanism. The unattacked carbon retains its C–O bond during opening. Product stereochemistry then requires mapping the original three-dimensional substituents, not assuming the whole molecule becomes racemic.
Acid-catalyzed epoxide opening has different activation and regioselectivity considerations, but strongly basic Grignard reagents cannot simply be combined with a strongly acidic medium and expected to remain active. Reagent compatibility prevents mixing the acid-opening rule into the ordinary organometallic-opening sequence.
ORIGINAL WORKED EXAMPLE
Distinguish one-carbon and two-carbon alcohol homologation
An ethylmagnesium reagent is reacted separately with formaldehyde or ethylene oxide, each followed by protonating workup. Identify the two alcohols.
Formaldehyde contributes one carbon to the ethyl group, giving CH₃CH₂CH₂OH.
Ethylene oxide contributes two carbons, giving CH₃CH₂CH₂CH₂OH.
The workup supplies the proton on oxygen rather than another carbon.
Answer Propan-1-ol from formaldehyde; butan-1-ol from ethylene oxide.
08 / UNDERSTAND & APPLY
8. Softer carbon reagents can change selectivity
Lithium diorganocuprates, often written R₂CuLi in a simplified formula, are organocopper reagents used for selected carbon–carbon bond-forming reactions. Their reactivity differs from that of RMgX or RLi, so they can offer useful selectivity rather than simply acting as weaker copies in every situation.
A suitable organic halide can couple with an organocuprate to form R–R′. The compatibility and substitution pattern of the electrophile matter; methyl and primary alkyl electrophiles are common elementary examples. Do not assume that an arbitrary tertiary halide gives a clean substitution product without elimination or other complications.
In a conventional simple Gilman coupling equation, one transferable R group is commonly counted per R₂CuLi formula unit for the stated reaction, with the other remaining in copper-containing by-products. Counting two product molecules automatically because two R groups appear in the reagent formula can be wrong.
Organocuprates can also perform conjugate 1,4 addition to suitable alpha,beta-unsaturated carbonyl compounds. The carbon group attaches at the beta carbon, and workup restores a carbonyl-containing product after enolate protonation. Stronger organolithium or Grignard reagents often favour direct 1,2 carbonyl addition in elementary comparisons, although substrate and conditions can modify this.
Acyl chloride reaction with a suitable organocuprate can provide a ketone without the usual double addition associated with Grignard reagents. This illustrates a general planning principle: select a reagent for the desired level of reaction, rather than trying to enforce single addition solely by using less of a strongly reactive reagent.
Modern transition-metal-catalyzed cross-couplings include several organometallic partner classes and catalytic cycles. A named coupling is not a universal license to join any two fragments. For this lesson’s elementary sequences, use only the stated compatible electrophile and reagent class, and do not infer an unshown catalyst.
09 / UNDERSTAND & APPLY
9. Design backward, then verify forward
For a tertiary alcohol, draw the three carbon groups attached to the alcohol carbon. Disconnect one of those C–C bonds to suggest a ketone plus an organometallic reagent. Several formal disconnections may exist, but equivalent groups can make some choices redundant, and incompatible functional groups can make a formal choice unsuitable.
For a secondary alcohol, an aldehyde plus a carbon nucleophile is a natural disconnection. For a primary alcohol RCH₂OH, formaldehyde addition is one option. For RCH₂CH₂OH, ethylene-oxide opening may be useful. The target’s OH position and carbon skeleton distinguish these patterns.
For a ketone, a nitrile plus a carbon nucleophile followed by hydrolysis or a suitable acyl chloride/organocopper route can avoid direct ketone overaddition. An ordinary ester plus one equivalent of Grignard should not be assumed to stop cleanly at ketone without specific supporting chemistry.
After selecting a route, run it forward on paper. Mark the transferred carbon group, the electrophilic carbon, any leaving group and the workup transformation. Check all carbons, oxygen and nitrogen atoms. Then count reagent equivalents consumed by acidic protons as well as those needed for carbon addition.
A numerical reagent-limiting problem should state ideal selectivity and complete reaction if it expects a single theoretical product amount. Real multistep yields and side reactions need empirical data. The original problems here use explicit ideal assumptions and do not claim practical isolated yields.
ORIGINAL WORKED EXAMPLE
Count ester equivalents before yield
A model ester reaction requires two methyl-transfer equivalents per ester and has no acidic-proton side consumption. There are 0.0150 mol ester and 0.0240 mol available methylmagnesium reagent. Assuming only complete double-addition product forms from the reacted ester, find the maximum product amount.
Two reagent equivalents are required for each product molecule.
The reagent can support 0.0240/2=0.0120 mol product.
The ester supply could support 0.0150 mol, so reagent is limiting.
The stated ideal selectivity assumption is essential because partial-addition mixtures are otherwise possible.
Answer 0.0120 mol maximum double-addition alcohol under the stated ideal model.
10 / UNDERSTAND & APPLY
10. Original solved practice
For each prediction, distinguish the product before and after workup and check whether a proton-transfer reaction would consume the reagent first.
ORIGINAL PRACTICE · 1
A methylmagnesium reagent is quenched with D₂O in an ideal isotope-mapping experiment. Give the organic product.
Reveal answer & reasoning
CH₃D.
Deuterium attaches at the carbon formerly bonded to magnesium; no new carbon is added.
ORIGINAL PRACTICE · 2
What alcohol results from formaldehyde plus an n-propylmagnesium reagent, followed by workup?
Reveal answer & reasoning
Butan-1-ol.
The three-carbon propyl fragment gains the one formaldehyde carbon as CH₂OH.
ORIGINAL PRACTICE · 3
What alcohol results from propanal plus methylmagnesium reagent, followed by workup?
Reveal answer & reasoning
Butan-2-ol.
The aldehyde carbon retains H and ethyl and gains methyl, becoming CH(OH) bonded to those two carbon groups.
ORIGINAL PRACTICE · 4
What alcohol results from propanone plus methylmagnesium reagent, followed by workup?
Reveal answer & reasoning
2-Methylpropan-2-ol.
The carbonyl carbon already has two methyl groups and gains a third.
ORIGINAL PRACTICE · 5
Does a formate ester necessarily give a tertiary alcohol with two identical Grignard additions?
Reveal answer & reasoning
No; it gives R₂CHOH, a secondary alcohol in the standard model.
The original acyl substituent is H, so the alcohol carbon retains one H after two carbon additions.
ORIGINAL PRACTICE · 6
Where does the nitrile carbon go in nitrile/Grignard ketone synthesis?
Reveal answer & reasoning
It becomes the ketone carbonyl carbon.
Nitrogen leaves during hydrolysis, while the nitrile carbon remains between the two carbon substituents.
ORIGINAL PRACTICE · 7
What acid results from phenylmagnesium reagent plus CO₂, then acid workup?
Reveal answer & reasoning
Benzoic acid.
The six-carbon phenyl group gains one CO₂ carbon as the carboxyl carbon.
ORIGINAL PRACTICE · 8
How many carbons does ethylene oxide add to the organometallic R skeleton in the standard opening?
Reveal answer & reasoning
Two.
Both epoxide carbons remain in RCH₂CH₂OH after workup.
ORIGINAL PRACTICE · 9
Why is aqueous acid written as a later step rather than mixed with active Grignard reagent from the start?
Reveal answer & reasoning
It would protonate and consume the reagent.
The carbon–carbon bond-forming stage must precede the protonating or hydrolytic workup in the conceptual sequence.
ORIGINAL PRACTICE · 10
In ethyl acetate plus two methyl-transfer equivalents, do the ethoxy carbons remain in the main tertiary alcohol?
Reveal answer & reasoning
No.
The ethoxy group leaves in the acyl-substitution stage and gives a separate ethanol-derived product; the acyl methyl and two incoming methyl groups form tert-butanol.
ORIGINAL PRACTICE · 11
For a specified cuprate 1,4 addition to an enone, at which carbon does the transferred group attach?
Reveal answer & reasoning
The beta carbon of the alpha,beta-unsaturated carbonyl system.
The product initially has enolate character and regains the carbonyl after suitable workup.
ORIGINAL PRACTICE · 12
A target tertiary alcohol has ethyl, methyl and phenyl attached to C(OH). Give one ketone/Grignard disconnection.
Reveal answer & reasoning
Acetophenone plus an ethylmagnesium reagent, followed by workup.
Acetophenone supplies phenyl and methyl on the carbonyl carbon; ethyl is the incoming third carbon group. The product is 2-phenylbutan-2-ol.
KEEP THE BIG IDEAS
Quick revision
Organometallic carbon is both nucleophilic and basic.
Acidic protons can consume reagent before addition.
Carbonyl carbon stays in the product; workup changes O/N bonding or protonation.
Esters usually need two transfers, while nitriles release ketones during hydrolysis.
CO₂ adds one carbon and ethylene oxide adds two.
Reagent class determines selectivity and cannot be interchanged blindly.
The teaching notes, worked explanations and original practice are written for this lesson. Separately labeled selected exam questions identify their exam, year, source and whether wording is paraphrased or an exact excerpt. Educational references do not certify current exam coverage.