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Breathing and Exchange of Gases · TOPIC LESSON

Gas Transport

Use gradients, binding and reversible chemistry to explain oxygen delivery and carbon-dioxide removal.

NEET UG40 min study guide12 indexed sections

BY THE END, YOU CAN

  • Predict exchange direction from gas-specific partial pressures.
  • Apply area/thickness diffusion comparisons with explicit assumptions.
  • Distinguish oxygen pressure, saturation, capacity and content.
  • Interpret dissociation-curve shifts and Bohr/Haldane effects.
  • Trace bicarbonate and chloride movements at tissues and lungs.
  • Calculate content differences and oxygen extraction with compatible units.

BEFORE YOU START

  • Blood components and circulation
  • Diffusion, enzymes and reversible reactions
  • Fractions and unit conversions

Original educational lesson. Work through the examples before revealing the practice answers. Check the current official syllabus separately; historical question frequency does not establish eligibility or predict future questions.

CONNECT THE CONCEPT TO THE EXAM

Selected exam questions & worked solutions

These selected examples are separate from the original practice below. Each identifies its exam, year and wording. They do not represent every paper or every selected year.

No source-verified exam questions have been published for this lesson yet. The worked examples and practice below are original teaching material, not past-exam questions.

01 / UNDERSTAND & APPLY

1. Separate ventilation, diffusion, circulation and metabolism

Oxygen delivery involves several connected processes. Ventilation renews air in the lungs, diffusion moves gases across exchange barriers, circulation transports substances between organs, and cells use oxygen in aerobic metabolism. A failure at one link cannot always be corrected simply by increasing a different link.

Carbon dioxide follows the reverse overall route from metabolically active tissues toward the lungs, but its chemical forms in blood differ from those of oxygen. Blood is therefore more than a pipe containing dissolved air: haemoglobin binding, buffering and reversible reactions greatly increase transport capacity.

The phrase gas exchange usually refers to movement between alveolar air and pulmonary blood or between systemic blood and tissues. Gas transport refers to carriage through blood between these sites. Cellular respiration is the metabolic process that uses oxygen and produces carbon dioxide in many pathways, rather than the mechanical movement of air.

This lesson uses human physiology and simplified quantitative models. Representative textbook values describe particular resting conditions, not universal constants. All numerical questions are original educational examples, and no result is intended to diagnose oxygen delivery in an individual.

02 / UNDERSTAND & APPLY

2. Each gas follows its own partial-pressure gradient

For a gas mixture, a gas’s partial pressure is its contribution to the total pressure. In an ideal dry mixture it equals mole fraction multiplied by total pressure. Oxygen can diffuse one way while carbon dioxide diffuses the other because each gas responds to its own gradient, not to a single combined “respiratory gas concentration”.

At a typical lung exchange interface, alveolar oxygen partial pressure exceeds that of the arriving pulmonary capillary blood, favouring oxygen movement into blood. Arriving blood has a higher carbon-dioxide partial pressure than alveolar gas, favouring carbon-dioxide movement into the alveolus.

At systemic tissues, ongoing oxygen use helps maintain a lower tissue oxygen partial pressure than in incoming arterial blood. Carbon-dioxide production helps maintain the opposite gradient for that gas. The gradients change as exchange progresses; a fixed starting difference is not necessarily maintained along the entire capillary.

Partial pressure in a liquid reflects the freely dissolved gas in equilibrium with a gas phase. Oxygen bound to haemoglobin increases total oxygen content without contributing directly to the dissolved-gas partial pressure in the same way. Thus two blood samples can have similar oxygen partial pressure but different total oxygen content.

Inspired dry air, humidified conducting-airway gas and alveolar gas are not interchangeable. Water vapour contributes part of total pressure, and alveolar gas also reflects mixing with residual gas and ongoing exchange. Multiplying the dry atmospheric oxygen fraction by total pressure does not directly give the alveolar oxygen partial pressure.

03 / UNDERSTAND & APPLY

3. Surface area, thickness and solubility control the rate

The alveolar–capillary barrier includes thin alveolar epithelium, the intervening basement-membrane/interstitial region and capillary endothelium. Gas also traverses the surface lining layer and blood compartments. The thin barrier and large total area favour exchange; this is a structural explanation rather than an active pump carrying oxygen across the wall.

A useful simplified diffusion relation is rate proportional to D × A × ΔP / T, where D incorporates gas/material properties, A is exchange area, ΔP is the partial-pressure difference and T is barrier thickness. It is a comparative model under otherwise similar conditions, not a complete prediction of whole-lung performance.

If area is halved and thickness doubles with D and ΔP unchanged, the predicted rate becomes one quarter of the original. If both area and gradient double while thickness stays fixed, the predicted rate becomes four times as large. State the held-constant factors before multiplying ratios.

Carbon dioxide is much more soluble than oxygen in the relevant fluids, allowing substantial transfer despite a smaller partial-pressure gradient. A smaller ΔP does not automatically mean less transfer when the diffusion properties differ. Comparing two gases requires more than comparing the gradient alone.

Barrier thickening, loss of functional area, inadequate blood supply and inadequate air renewal can each limit exchange through different mechanisms. A larger geometric airspace does not necessarily mean more exchange surface: destruction of walls between many small alveolar spaces can reduce total surface area.

04 / UNDERSTAND & APPLY

4. Fresh air and blood must meet at the same place

Ventilation supplies alveolar gas, while perfusion supplies pulmonary capillary blood. A well-ventilated region with essentially no blood flow contributes little oxygen uptake into the circulation. A perfused region receiving essentially no fresh air cannot sustain normal exchange merely because blood is passing it.

Idealised high and low ventilation–perfusion situations explain why total air moved is not enough to characterise effective exchange. Regional matching matters. These are conceptual limiting cases, not labels to apply to someone from a symptom description.

Blood flow and ventilation also maintain gradients by replacing material that has approached local equilibrium. Diffusion can be passive even though the overall respiratory and circulatory systems expend energy to maintain the conditions supporting it.

At steady state, delivery, uptake and removal must be considered as fluxes per time. A concentration measured at one point gives different information from the total amount transported through that point each minute. Multiplying content by blood flow connects those two kinds of quantity.

05 / UNDERSTAND & APPLY

5. Haemoglobin adds capacity beyond dissolved oxygen

Most oxygen carried in ordinary human blood is reversibly associated with haemoglobin inside erythrocytes; a much smaller fraction is physically dissolved. NCERT’s approximate classroom partition is about 97% haemoglobin-associated and 3% dissolved, while other references use somewhat different resting estimates. The robust conclusion is the dominant haemoglobin contribution, not an immutable percentage.

A typical adult haemoglobin molecule contains four haem groups, each able to bind one O₂ molecule. Full occupancy therefore gives four O₂ molecules per haemoglobin molecule. Percentage saturation describes the fraction of available oxygen-binding sites occupied, not the fraction of all blood molecules that are oxygen.

Oxygen binding is reversible. In the lungs, sufficiently high dissolved oxygen partial pressure favours loading; in tissues, removal of dissolved oxygen favours release from haemoglobin. This coupling permits a large quantity of oxygen to be moved without requiring all of it to remain freely dissolved.

Capacity, saturation and content must be distinguished. Capacity depends strongly on how much functional haemoglobin is present. Saturation is a proportion of its available sites. Content is an amount of oxygen per volume of blood, including bound and dissolved fractions. High saturation alone does not prove high content if the amount of haemoglobin differs.

Ordinary oxygenation is not described as converting haem iron from Fe²⁺ to Fe³⁺. Reversible oxygen binding in the useful haemoglobin form preserves the functional ferrous state. Also, deoxygenated blood is not oxygen-free: substantial oxygen commonly remains bound after resting tissue extraction.

06 / UNDERSTAND & APPLY

6. Cooperativity produces a sigmoid relationship

The oxygen–haemoglobin dissociation curve plots saturation against oxygen partial pressure under specified conditions. Its sigmoid shape reflects cooperative interactions among haemoglobin subunits: binding at one site changes the likelihood of binding at other sites.

The relatively steep middle region means a moderate fall in partial pressure can be associated with substantial unloading. The flatter high-pressure region means a comparable pressure change may produce a smaller saturation change. A straight-line model across the whole range therefore misses the functional shape.

A movement along one curve results from changing oxygen partial pressure while the factors defining that curve remain fixed. A shift of the curve means that, at the same oxygen partial pressure, saturation differs because affinity has changed. These two operations must not be confused.

A rightward shift indicates lower affinity: a higher oxygen partial pressure is needed to reach the same saturation. At a specified tissue partial pressure, this generally favours unloading relative to the original curve. A leftward shift indicates higher affinity and greater saturation at that same partial pressure.

P₅₀ is the oxygen partial pressure at 50% saturation under the stated conditions. A higher P₅₀ corresponds to lower affinity. It is not the pressure at which every site is occupied, nor the percentage of oxygen extracted by a tissue.

Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.

Illustrative oxygen-binding curvesTwo original Hill-type curves use saturation S equals P cubed divided by P cubed plus P50 cubed. Curve A has P50 25 and curve B P50 40, so B is right-shifted with lower affinity. At P 40, A is approximately 80 percent saturated and B is 50 percent.A right shift means lower affinity at the same PO₂Illustrative cooperative-binding model; not measured human data0255075100020406080100Oxygen partial pressure (arbitrary pressure units)Haemoglobin-site saturation (%)A: P₅₀ = 25B: P₅₀ = 40At PO₂ = 40: A ≈ 80% occupied; B = 50% occupied.Both curves use S = P³ / (P³ + P₅₀³); the exponent is illustrative.Changing P moves along a curve; changing P₅₀ shifts the curve.
Invented cooperative-binding model in arbitrary pressure units, not a calibrated physiological curve or clinical reference. The exponent of three is a stated illustrative assumption. P50 is the pressure at half saturation.

07 / UNDERSTAND & APPLY

7. Active tissues alter the conditions for unloading

Increased carbon dioxide and increased hydrogen-ion concentration, meaning lower pH, generally reduce haemoglobin’s oxygen affinity. This is the central Bohr-effect association. Increased temperature and increased erythrocyte 2,3-bisphosphoglycerate also tend to favour a rightward shift in the usual physiological model.

Active tissues can simultaneously consume oxygen, produce carbon dioxide and release heat. Lower local oxygen partial pressure moves blood along the curve, while altered pH or temperature can shift the curve. The same episode can therefore involve both a change in position and a change in affinity.

Higher affinity is not always equivalent to better tissue delivery. It can help loading at low available oxygen pressure but also retain oxygen more strongly during unloading. The relevant outcome depends on both ends of the route, blood flow, haemoglobin amount and tissue demand.

Fetal haemoglobin has a higher oxygen affinity than typical adult haemoglobin under comparable conditions, associated in part with different interaction with 2,3-BPG. This supports oxygen transfer across the placenta. It does not mean maternal and fetal blood normally mix freely, or that every molecule carries more than four oxygen molecules.

Carbon monoxide and carbon dioxide are chemically different gases. Carbon monoxide can bind strongly to haemoglobin and interfere with oxygen carriage; carbon dioxide normally participates in reversible transport and acid–base physiology. The similar abbreviations CO and CO₂ must not be treated as interchangeable. This distinction is conceptual, not guidance for managing exposure.

08 / UNDERSTAND & APPLY

8. Carbon dioxide travels in three major forms

Carbon dioxide is transported dissolved, bound to amino groups on proteins such as haemoglobin, and predominantly as bicarbonate under typical resting conditions. Introductory approximate partitions are around 70% bicarbonate, 20–25% carbamino forms and a smaller dissolved fraction. These rounded estimates should not be combined as if every endpoint were simultaneously exact.

Carbaminohaemoglobin forms when carbon dioxide associates with globin amino groups. This is a different binding location from oxygen’s haem site and a different compound from carboxyhaemoglobin, the term associated with carbon monoxide. Similar names are a frequent source of mistaken matching.

Inside erythrocytes, carbonic anhydrase greatly accelerates reversible hydration of CO₂ to carbonic acid; acid–base equilibrium connects carbonic acid with H⁺ and HCO₃⁻. The combined relationship is CO₂ + H₂O ⇌ H₂CO₃ ⇌ H⁺ + HCO₃⁻. The catalyst speeds equilibration but does not change the equilibrium constant by itself.

At tissues, incoming carbon dioxide supports net bicarbonate production, while haemoglobin and other buffers bind part of the associated hydrogen-ion load. Much bicarbonate leaves erythrocytes for the plasma in exchange for chloride entering the cells. This chloride shift preserves charge balance for the anion exchange.

At the lungs, the net sequence reverses: bicarbonate re-enters erythrocytes as chloride leaves, hydrogen ions combine with bicarbonate, and carbon dioxide is regenerated and diffuses toward alveolar gas. It is CO₂ gas, not a stream of bicarbonate ions, that is ultimately exhaled.

Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.

Opposite chloride-shift directions at tissues and lungsAt tissues carbon dioxide enters erythrocytes, where reversible reactions form bicarbonate and hydrogen ions; bicarbonate moves outward to plasma as chloride enters. At lungs bicarbonate enters erythrocytes while chloride leaves, and reactions regenerate carbon dioxide for diffusion toward alveolar air. Haemoglobin buffers hydrogen ions.Bicarbonate transport: follow the membrane directionsNet tissue and lung directions reverse; reactions remain reversibleAT TISSUESERYTHROCYTEPLASMACO₂ + H₂O ⇌ H₂CO₃H₂CO₃ ⇌ H⁺ + HCO₃⁻Carbonic anhydrase accelerates hydrationHaemoglobin buffers H⁺HCO₃⁻ leaves → plasmaCl⁻ enters ← plasmaCO₂ enters from tissuesAT LUNGSERYTHROCYTEPLASMACO₂ + H₂O ⇌ H₂CO₃H₂CO₃ ⇌ H⁺ + HCO₃⁻Carbonic anhydrase accelerates hydrationOxygenation promotes H⁺ releaseHCO₃⁻ enters ← plasmaCl⁻ leaves → plasmaCO₂ leaves toward alveoliBicarbonate is converted back toward CO₂; bicarbonate ions are not exhaled.
Original two-compartment mechanism map. Arrows show net anion-exchange directions, not every transport reaction or quantitative flux. Carbonic anhydrase speeds carbon-dioxide hydration and its reverse without changing equilibrium.

09 / UNDERSTAND & APPLY

9. The two gases influence each other’s carriage

The Bohr effect asks how carbon dioxide and acidity influence oxygen affinity. The Haldane effect asks how oxygenation influences carbon-dioxide carriage and hydrogen-ion buffering. Naming which variable changes and which transport property responds prevents the two effects from being swapped.

Deoxygenated haemoglobin supports greater carbon-dioxide carriage and hydrogen-ion buffering than oxygenated haemoglobin under otherwise comparable conditions. Oxygen loading in the lungs promotes release of carbon dioxide and hydrogen ions, helping drive bicarbonate back toward exhalable CO₂.

The effects complement each other: tissue conditions favour oxygen unloading and carbon-dioxide uptake, while lung conditions favour oxygen uptake and carbon-dioxide release. This does not mean one gas must bind at precisely the same site to displace the other. Different binding and buffering processes are coupled through haemoglobin’s state.

Reversibility is essential. A one-way conversion that permanently trapped all carbon dioxide as bicarbonate would not explain its release in the lungs. Follow both the tissue and lung arrows whenever interpreting a transport diagram.

10 / UNDERSTAND & APPLY

10. Quantify what actually leaves the circulation

For a deliberately simplified bound-oxygen model, content equals oxygen-binding capacity per blood volume multiplied by fractional saturation. If capacity is 20 mL O₂ per 100 mL blood and saturation is 75%, bound content is 15 mL O₂ per 100 mL. Any dissolved component must be added separately if the problem includes it.

Oxygen delivered to a tissue per minute depends on incoming content and blood flow. Oxygen extracted per minute depends on the arterial–venous content difference multiplied by flow, provided the defined tissue is in a suitable steady state. Use compatible volume units and distinguish delivery from extraction.

If incoming and outgoing contents are 20 and 15 mL O₂ per 100 mL blood, each 100 mL supplies a net 5 mL O₂. At a stipulated blood flow of 5 L per minute, there are fifty 100-mL units per minute, so extraction is 250 mL O₂ per minute. The incoming delivery is instead 1000 mL O₂ per minute in that model.

Neither total lung air volume nor blood oxygen saturation alone supplies all inputs to that calculation. A complete explanation asks which amount, fraction, pressure, gradient or flow the question provides. These quantities are related, but each has a distinct denominator and physical meaning.

11 / UNDERSTAND & APPLY

11. Eight original worked cases

Use only the stated model and quantities; the examples are not individual medical assessments.

ORIGINAL WORKED EXAMPLE

Predict both directions

An invented alveolar compartment has PO₂ 100 and PCO₂ 40 mmHg; arriving blood has PO₂ 40 and PCO₂ 46 mmHg. Predict initial diffusion directions.

  1. Compare oxygen with oxygen: 100 > 40, so oxygen moves toward blood.
  2. Compare carbon dioxide with carbon dioxide: 46 > 40, so carbon dioxide moves toward alveolar gas.
  3. Different gases can move in opposite directions across the same barrier.

Answer O₂ alveolus → blood; CO₂ blood → alveolus.

ORIGINAL WORKED EXAMPLE

Change area and thickness

In a simple diffusion model, area becomes half and thickness becomes twice the original. D and ΔP stay fixed. Find the rate ratio.

  1. Use rate proportional to A/T.
  2. New/old = (1/2)/2.
  3. No claim is made that all real lung variables remain unchanged.

Answer One quarter of the original rate.

ORIGINAL WORKED EXAMPLE

Separate saturation from content

Two model samples have capacities 20 and 12 mL O₂ per 100 mL. Both are 90% saturated; ignore dissolved oxygen. Find contents.

  1. Multiply each capacity by 0.90.
  2. The first gives 18 and the second 10.8 mL O₂ per 100 mL.
  3. Equal saturation does not equal equal content.

Answer 18 and 10.8 mL O₂ per 100 mL blood.

ORIGINAL WORKED EXAMPLE

Read a shift at fixed pressure

At the same PO₂, curve B has lower saturation than curve A. Which has lower affinity under the stated comparison?

  1. Hold the x-axis value fixed.
  2. Lower saturation means fewer sites occupied at that same available pressure.
  3. Curve B is shifted toward requiring greater pressure for the same saturation.

Answer B has lower affinity; it is right-shifted relative to A.

ORIGINAL WORKED EXAMPLE

Follow the chloride shift

At a tissue site, bicarbonate leaves an erythrocyte through an anion exchanger. Which ion movement accompanies it?

  1. Bicarbonate carries negative charge.
  2. The exchanger brings chloride into the erythrocyte in the opposite direction.
  3. At the lung, the net directions reverse.

Answer Chloride enters the erythrocyte.

ORIGINAL WORKED EXAMPLE

Name the coupling

Oxygen loading reduces haemoglobin’s capacity to support CO₂ carriage and H⁺ buffering. Which named effect is illustrated?

  1. The input change is oxygenation.
  2. The response concerns carbon dioxide carriage and buffering.
  3. That direction of influence defines the Haldane effect, rather than the Bohr effect.

Answer Haldane effect.

ORIGINAL WORKED EXAMPLE

Compute net extraction

Model arterial and venous oxygen contents are 18 and 14 mL per 100 mL blood. Flow is 4 L/min. Find extraction.

  1. Difference = 4 mL O₂ per 100 mL blood.
  2. 4 L is 4000 mL, or forty 100-mL units.
  3. Extraction = 4 × 40 = 160 mL O₂/min.

Answer 160 mL O₂ per minute.

ORIGINAL WORKED EXAMPLE

Do not exhale the wrong chemical form

A student says plasma bicarbonate is pumped directly into alveolar air. Repair the route.

  1. Bicarbonate returns to erythrocytes in the lung exchange region.
  2. Reversible reactions regenerate CO₂, facilitated by carbonic anhydrase.
  3. CO₂ diffuses into alveolar gas and is removed by ventilation.

Answer Bicarbonate is converted back toward CO₂ before the gas is exhaled.

12 / UNDERSTAND & APPLY

12. Original solved practice

Keep pressure, saturation, content and flow distinct.

ORIGINAL PRACTICE · 1

What distinguishes partial pressure from total oxygen content?

Reveal answer & reasoning

Partial pressure reflects freely dissolved oxygen; content includes bound oxygen.

Haemoglobin can increase content greatly without a proportional increase in dissolved PO₂.

ORIGINAL PRACTICE · 2

A dry ideal mixture is 20% oxygen at total pressure 600 mmHg. Find oxygen partial pressure.

Reveal answer & reasoning

120 mmHg.

0.20 × 600; this is not automatically the alveolar value.

ORIGINAL PRACTICE · 3

What happens to model diffusion rate if thickness triples and all other terms are fixed?

Reveal answer & reasoning

It becomes one third.

Rate is inversely proportional to thickness in the stated approximation.

ORIGINAL PRACTICE · 4

How many O₂ molecules can one fully occupied typical haemoglobin molecule carry?

Reveal answer & reasoning

Four.

There are four haem oxygen-binding sites.

ORIGINAL PRACTICE · 5

Does deoxygenated venous blood necessarily contain zero oxygen?

Reveal answer & reasoning

No.

The term is relative; oxygen commonly remains bound and dissolved.

ORIGINAL PRACTICE · 6

What does a larger P₅₀ indicate under comparable conditions?

Reveal answer & reasoning

Lower oxygen affinity.

More oxygen partial pressure is needed for 50% saturation.

ORIGINAL PRACTICE · 7

At constant PO₂, which usual change favours unloading: lower pH or higher pH?

Reveal answer & reasoning

Lower pH.

The Bohr-effect association shifts affinity toward oxygen release.

ORIGINAL PRACTICE · 8

What is the dominant typical chemical form of transported CO₂?

Reveal answer & reasoning

Bicarbonate.

Dissolved and carbamino fractions also contribute.

ORIGINAL PRACTICE · 9

Where does CO₂ bind when forming carbaminohaemoglobin?

Reveal answer & reasoning

Globin amino groups.

It is not the haem iron oxygen-binding site.

ORIGINAL PRACTICE · 10

Does carbonic anhydrase make an otherwise reversible reaction intrinsically one-way?

Reveal answer & reasoning

No.

It accelerates equilibration in both directions without changing equilibrium by itself.

ORIGINAL PRACTICE · 11

At lung capillaries, in which direction does chloride move during the reverse chloride shift?

Reveal answer & reasoning

Out of the erythrocyte.

Bicarbonate enters in exchange.

ORIGINAL PRACTICE · 12

Which effect names increased acidity reducing oxygen affinity?

Reveal answer & reasoning

Bohr effect.

Haldane concerns oxygenation influencing carbon-dioxide carriage and buffering.

ORIGINAL PRACTICE · 13

Ignoring dissolved oxygen, capacity 16 mL/100 mL and saturation 75% give what content?

Reveal answer & reasoning

12 mL O₂ per 100 mL.

16 × 0.75 = 12.

ORIGINAL PRACTICE · 14

A content difference is 5 mL/100 mL and flow is 3 L/min. Find extraction.

Reveal answer & reasoning

150 mL O₂/min.

3 L contains thirty 100-mL units, and 30 × 5 = 150.

KEEP THE BIG IDEAS

Quick revision

  • Each gas follows its own partial-pressure gradient.
  • Dissolved pressure and total bound-plus-dissolved content are different.
  • Haemoglobin cooperativity gives a sigmoid saturation curve.
  • A right shift means lower affinity at the same PO₂.
  • Most CO₂ is transported as bicarbonate and regenerated as CO₂ in the lungs.
  • Chloride enters erythrocytes at tissues and leaves during the reverse shift at lungs.
  • Bohr: acidity/CO₂ affect O₂ affinity; Haldane: oxygenation affects CO₂ carriage.
  • Net extraction equals blood flow times the arterial–venous content difference under the stated steady-state model.
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References & scope

The teaching notes, worked explanations and original practice are written for this lesson. Separately labeled selected exam questions identify their exam, year, source and whether wording is paraphrased or an exact excerpt. Educational references do not certify current exam coverage.

  • NCERT Biology, Class XI, Breathing and Exchange of Gases

    Inspected 2026–27 chapter, exchange and transport sections. Rounded transport fractions are curricular approximations, not exact universal partitions.

  • OpenStax Anatomy and Physiology 2e, Gas Exchange ↗

    Inspected partial-pressure and ventilation/perfusion context. Original examples distinguish gas-specific gradients and content.

  • OpenStax Anatomy and Physiology 2e, Transport of Gases ↗

    Inspected oxygen binding and reversible bicarbonate/anion-exchange mechanisms. No diagnostic or exposure-management instructions reproduced.

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