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Respiration in Plants · TOPIC LESSON

Electron Transport and Oxidative Phosphorylation

Track carbon, electrons, protons and ATP through plant-cell respiration without mixing their accounts.

NEET UG55 min study guide12 indexed sections

BY THE END, YOU CAN

  • Locate the major respiratory stages and balance their carbon and carrier outputs.
  • Explain glycolytic investment and substrate-level phosphorylation.
  • Follow pyruvate oxidation and two turns of the citric acid cycle per glucose.
  • Distinguish electron flow from proton transport and ATP synthesis.
  • Predict effects of oxygen limitation, respiratory inhibition and uncoupling under stated conditions.

BEFORE YOU START

  • Oxidation transfers electrons to an acceptor.
  • ATP hydrolysis can support cellular work; membranes separate aqueous compartments.

Original educational lesson. Work through the examples before revealing the practice answers. Check the current official syllabus separately; historical question frequency does not establish eligibility or predict future questions.

CONNECT THE CONCEPT TO THE EXAM

Selected exam questions & worked solutions

These selected examples are separate from the original practice below. Each identifies its exam, year and wording. They do not represent every paper or every selected year.

No source-verified exam questions have been published for this lesson yet. The worked examples and practice below are original teaching material, not past-exam questions.

01 / UNDERSTAND & APPLY

Respiration is cellular energy conversion

Cellular respiration transfers part of the free energy released by oxidation of organic substrates into usable forms, particularly ATP. It is not identical to breathing or external gas exchange. Plants respire in roots, stems, leaves and other living tissues during both day and night. A photosynthesising leaf may take up carbon dioxide overall in daylight because photosynthetic uptake exceeds respiratory release; the net gas measurement does not show that respiration stopped.

For complete aerobic oxidation of one glucose, six carbons ultimately leave as six carbon dioxide molecules and oxygen serves as the final electron acceptor. Water is produced at the terminal respiratory reaction, although water also participates in other pathway steps. The net equation is an overall balance, not a description of one explosive reaction in the cell. Many enzyme-catalysed transfers release energy in manageable stages.

Keep four accounts separate. Carbon atoms move through organic intermediates and carbon dioxide. Electrons move to reduced carriers and finally an acceptor. Protons are redistributed across a membrane and contribute to an electrochemical gradient. ATP is made by particular reactions. A carbon count cannot by itself determine ATP yield, and movement of electrons down a chain is not the same as movement of protons through ATP synthase.

02 / UNDERSTAND & APPLY

The location determines the mechanism

In a typical aerobic eukaryotic cell, glycolysis occurs in the cytosol. Pyruvate enters mitochondria and is converted to acetyl-CoA in the matrix. Most citric acid cycle reactions are matrix reactions, while succinate dehydrogenase is embedded in the inner mitochondrial membrane and also functions as respiratory complex II. The electron-transport chain and ATP synthase are associated with this inner membrane.

The inner membrane separates the matrix from the intermembrane space. Its selective permeability permits a proton electrochemical gradient to persist. Cristae increase membrane area available for respiratory machinery. Simply having a large outer membrane is insufficient: the energy-conserving barrier and the correctly oriented proteins are essential. Prokaryotic respiratory chains use their plasma membrane rather than mitochondria, so respiration does not universally require that organelle.

Compartmentation also affects accounting. Cytosolic NADH does not simply diffuse across the intact inner mitochondrial membrane. Shuttle systems transfer its reducing equivalents into mitochondrial metabolism, and different routes can lead to different ATP returns. Transport of pyruvate, phosphate, ADP and ATP has energetic consequences. A theoretical total that ignores transport must be identified as a convention, not an invariant measured yield.

03 / UNDERSTAND & APPLY

Invest first, recover twice

Glycolysis converts a six-carbon glucose to two three-carbon pyruvate molecules through ten reactions. Two ATP are invested before the main cleavage. Glucose is phosphorylated, rearranged and phosphorylated again to form fructose-1,6-bisphosphate. The six-carbon compound is split into two triose phosphates, and their interconversion means two glyceraldehyde-3-phosphate molecules proceed through the payoff sequence per glucose.

Each triose is oxidised while NAD+ is reduced to NADH, and inorganic phosphate is incorporated into an intermediate. Two subsequent phosphate-transfer steps each produce one ATP per triose. Because the payoff sequence happens twice, four ATP are produced gross. Subtracting the two invested gives a net gain of two ATP per glucose, alongside two NADH and two pyruvate. There is no carbon dioxide release in ordinary glycolysis.

The two ATP-producing donor steps are 1,3-bisphosphoglycerate to 3-phosphoglycerate, catalysed by phosphoglycerate kinase, and phosphoenolpyruvate (PEP) to pyruvate, catalysed by pyruvate kinase. Each transfers phosphate to ADP. The preceding glyceraldehyde-3-phosphate dehydrogenase step is different: glyceraldehyde-3-phosphate is oxidised, NAD+ is reduced, and free inorganic phosphate is added to form 1,3-bisphosphoglycerate. That oxidation/Pi-addition step does not itself produce ATP or require a new ATP phosphate donation.

The direct transfer of phosphate from a metabolic intermediate to ADP is substrate-level phosphorylation. It does not require an electron-transport chain or a proton gradient. Glycolysis itself does not consume oxygen, but continued flux requires NAD+ to be regenerated from NADH. Therefore a pathway can be independent of direct oxygen use yet become indirectly limited when the cell loses its usual means of oxidising reduced carriers.

High ATP availability can restrain glycolytic flux, while greater demand and changes in energy-charge signals can favour it. Regulation is distributed and depends on organism, tissue and conditions; do not infer that one enzyme alone determines every rate. For exam reasoning, the decisive bookkeeping is two ATP invested, four produced gross, two NADH made and six carbons retained in two pyruvates.

Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.

Glycolytic branch accountingOne six-carbon glucose uses two ATP before splitting into two three-carbon branches. Each branch produces one NADH and two ATP gross before ending as pyruvate. The net ATP total is two.Glycolysis: one investment, two payoff branchesGlucose: 6 carbonsTwo triose phosphates2 ATP investedOne 3-carbon branch1 NADH + 2 ATP grossPyruvate: 3 carbonsOne 3-carbon branch1 NADH + 2 ATP grossPyruvate: 3 carbonsPer glucose: 2 pyruvate + 2 NADH + 4 ATP gross − 2 ATP investedNet gain = 2 ATP. No CO2 is released in glycolysis.
Original accounting diagram. Branch boxes summarise multiple enzyme steps; phosphate and water balances are omitted.

04 / UNDERSTAND & APPLY

The link reaction changes both carbon and carrier counts

Pyruvate oxidation converts a three-carbon pyruvate into a two-carbon acetyl group attached to coenzyme A. One carbon leaves as carbon dioxide and one NAD+ is reduced to NADH per pyruvate. Coenzyme A is an acyl-group carrier, not a second name for the electron carrier NAD+. This oxidative decarboxylation is catalysed by the pyruvate dehydrogenase complex.

One glucose supplies two pyruvates, so the link reactions together produce two acetyl-CoA, two carbon dioxide and two NADH. They do not directly generate ATP by substrate-level phosphorylation. If a question asks for products before entry into the citric acid cycle, do not include the cycle outputs prematurely.

Acetyl-CoA is a metabolic junction. Fatty acid oxidation also supplies acetyl units, while carbon skeletons from amino acids can enter at several points after appropriate processing. The glucose-specific totals are therefore not universal totals for every respiratory substrate. State the starting molecule before calculating products.

05 / UNDERSTAND & APPLY

A regenerated acceptor allows repeated oxidation

The citric acid cycle, also called the Krebs or tricarboxylic acid cycle, begins when a two-carbon acetyl group combines with four-carbon oxaloacetate to form six-carbon citrate. Rearrangements and two oxidative decarboxylations lead through a five-carbon intermediate to four-carbon compounds. Subsequent reactions regenerate oxaloacetate, which can accept another acetyl group. The acceptor is regenerated rather than consumed as a net product of each turn.

The conventional major sequence is citrate, isocitrate, alpha-ketoglutarate, succinyl-CoA, succinate, fumarate, malate and oxaloacetate. Per acetyl-CoA, three NADH are formed, one FAD-linked reduction occurs at succinate dehydrogenase, two carbon dioxide are released and one ATP or GTP equivalent is made by substrate-level phosphorylation. Depending on the enzyme system, the nucleotide product can differ; count one ATP equivalent for this step under the stated convention.

Two turns are needed for the two acetyl groups derived from one glucose. Thus the cycle contributes six NADH, two FADH2 equivalents, two substrate-level ATP equivalents and four carbon dioxide per glucose. Add the link reaction separately when a question asks for complete oxidation of both pyruvates. The first turn does not simply release the two incoming acetyl carbons as its two carbon dioxide molecules; carbon identities rearrange and are lost over subsequent turns.

The cycle does not directly consume molecular oxygen at its individual decarboxylation steps, but under usual aerobic conditions it depends on respiratory reoxidation of NADH and reduced flavins. Without adequate regeneration of oxidised carriers, flux falls. Intermediates also support biosynthesis, so replenishing reactions may be needed when intermediates are withdrawn. A pathway that contributes to both breakdown and synthesis is described as amphibolic.

Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.

Citric-cycle carbon and energy bookkeepingA two-carbon acetyl group joins four-carbon oxaloacetate to make six-carbon citrate. Two decarboxylations return the intermediates to four carbons, and subsequent reactions regenerate oxaloacetate. Reduced carriers and one substrate-level nucleotide are counted per turn.One cycle turn: keep the two energy-conserving steps distinctCitrate / isocitrate6 Cα-ketoglutarate5 CSuccinyl-CoA4 CSuccinate4 CFumarate4 CMalate4 COxaloacetate4 CNADH + CO2NADH + CO2ATP/GTPFAD-linked reductionNADHAcetyl-CoA: 2 CPer turn: 3 NADH, 1 FAD-linked reduction, 1 ATP/GTP equivalent, 2 CO2.Oxaloacetate is regenerated; two turns follow one glucose.
Original grouped early-intermediate diagram with explicit succinyl-CoA → succinate ATP/GTP production and succinate → fumarate FAD-linked reduction. Carbon labels are counts, not isotope identities.

06 / UNDERSTAND & APPLY

Carriers are recycled electron-transfer partners

NAD+ accepts a hydride equivalent, carrying two electrons and one proton as NADH; another proton may be released to the solution depending on the balanced reaction. NADH is therefore a reduced carrier, not an ATP molecule. Reoxidation returns NAD+ for further substrate oxidation. The NAD pool can cycle repeatedly, so two NADH formed per glucose does not mean two permanently consumed NAD molecules.

Flavins such as FAD are often enzyme-bound. The succinate dehydrogenase flavin accepts reducing equivalents during succinate oxidation and transfers electrons onward through the enzyme to the ubiquinone pool. Textbook bookkeeping calls this one FADH2 per cycle, but a free FADH2 molecule is not released to swim between complexes. This distinction matters when comparing a carrier balance with a structural diagram.

Ubiquinone, also called coenzyme Q, is a lipid-soluble mobile carrier in the inner membrane. Its reduced form ubiquinol can carry two electrons and protons. Cytochrome c is a small mobile protein on the intermembrane-space side and transfers one electron at a time between complexes III and IV. Iron-sulfur centres and cytochromes within complexes relay electrons through changes in oxidation state. The proteins remain in the system; their metal centres cycle rather than being consumed.

NADPH is central to many reductive biosynthetic and photosynthetic processes, while NADH has the principal bookkeeping role in the respiratory scheme here. Similar names do not justify replacing one with the other in a pathway balance. Determine which reaction and enzyme system the question specifies.

07 / UNDERSTAND & APPLY

Electron transfer powers proton separation

In the standard mitochondrial pathway, electrons from matrix NADH enter complex I and pass to ubiquinone. Electrons from succinate enter through complex II and also reach ubiquinone. From the reduced quinone pool they pass through complex III, cytochrome c and complex IV, where oxygen is reduced to water. Oxygen is not converted to carbon dioxide at complex IV; respiratory carbon dioxide arose from substrate decarboxylations earlier.

Complexes I, III and IV contribute to proton translocation from the matrix towards the intermembrane space. Complex II does not pump protons in the standard scheme. Electrons entering at complex II therefore bypass one energy-conserving step, which helps explain the lower ATP return associated with FAD-linked entry compared with matrix NADH. The electron route and the proton route must be drawn separately.

The resulting proton-motive force combines a concentration difference and an electrical potential difference. Protons can return through ATP synthase, whose membrane component provides a coupled route and whose catalytic head forms ATP from ADP and inorganic phosphate on the matrix side. The enzyme couples favourable proton movement to ATP synthesis. It does not make ATP merely because oxygen touches it, nor does it pump electrons through the membrane.

Oxidative phosphorylation names the coupling between substrate oxidation through respiratory electron transfer and phosphorylation of ADP. The chain establishes the gradient; ATP synthase uses it. An intact low-leak membrane, appropriate electron donors and acceptor, ADP and phosphate are all needed for sustained coupled ATP production. A chain without a retained gradient may still consume oxygen while making much less ATP.

Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.

Electron transfer and chemiosmotic couplingInner-membrane complexes I and II feed electrons to ubiquinone, then III, cytochrome c and IV. I, III and IV move protons from matrix to intermembrane space. Proton return through ATP synthase powers ATP formation on the matrix side. Oxygen receives electrons at IV to form water.Mitochondrial coupling: electrons, protons and ATP follow different routesIntermembrane space: proton accumulationMatrixIIIIIIIVVH+H+H+NADH → NAD+Succinate → fumarateQcyt cO2 → H2OH+F1 headADP + Pi → ATPGreen arrows: electron route. Red arrows: proton movement.I, III and IV pump outward; II does not. V = ATP synthase.
Original standard-pathway schematic. Arrows identify routes rather than exact stoichiometry; complex II is not a proton pump. Q includes the quinone/quinol pool.

08 / UNDERSTAND & APPLY

Different fates regenerate the carriers differently

When oxygen-supported respiratory oxidation cannot meet demand, fermentation can regenerate NAD+ in the cytosol. In alcoholic fermentation, pyruvate first loses carbon dioxide to form acetaldehyde, which is reduced to ethanol by NADH. In lactate fermentation, pyruvate is reduced directly to lactate without that decarboxylation. The fermentation reactions themselves provide no additional ATP beyond the net two from glycolysis in this standard glucose pathway.

Fermentation is not synonymous with all anaerobic respiration. Anaerobic respiration in suitable microorganisms uses an electron-transport chain with a terminal acceptor other than oxygen. In fermentation, an organic metabolite derived from the substrate accepts the electrons without the same respiratory-chain mechanism. For plant tissues under oxygen shortage, do not infer that a large aerobic ATP yield persists just because glucose is still consumed.

Plants can possess alternative respiratory routes, including alternative oxidase. These routes change how electron flow is coupled to proton pumping and can reduce ATP conservation per electron pair. Their existence is a reason to identify the standard cytochrome pathway as a model rather than assert that every plant mitochondrion has exactly the same ATP yield in every condition. The detailed alternative-pathway biochemistry is beyond the present accounting model.

Respiratory quotient, RQ, is carbon dioxide released divided by oxygen consumed, using equal molar or volume bases under comparable conditions. Complete carbohydrate oxidation gives RQ near one; fats generally give a lower ratio because more oxygen is required relative to carbon dioxide output. An RQ calculation needs both rates and a defined process. If no oxygen is consumed, dividing by zero does not yield an ordinary finite aerobic RQ.

09 / UNDERSTAND & APPLY

Declare the ATP convention before adding

Complete oxidation of one glucose through the standard pathway produces ten NADH in total: two glycolytic, two from pyruvate oxidation and six from the cycle. There are two FAD-linked reduction equivalents, two net glycolytic ATP and two cycle ATP equivalents. The direct substrate-level total is therefore four. The remaining ATP depends on coupling and transport rather than being attached automatically to every carrier symbol.

A modern illustrative accounting uses approximately 2.5 ATP per matrix NADH and 1.5 per FAD-linked electron pair. Treating all ten NADH as equivalent gives 10 × 2.5 + 2 × 1.5 + 4 = 32 ATP, whereas a lower-return route for the two cytosolic NADH can give about 30. Older textbook idealisations use 3 and 2 and produce a theoretical 38. These conventions must not be mixed, and none is an unconditional measured plant-cell yield.

An electron-transfer inhibitor blocks a specified chain step, often leaving upstream carriers more reduced and limiting proton pumping and oxygen consumption. An uncoupler increases proton leak, weakening ATP synthesis without necessarily stopping electron transfer; oxidation can continue or accelerate if substrates and oxygen are available. An ATP-synthase inhibitor blocks the main proton-return route, initially increasing back-pressure on further pumping. These predictions assume an otherwise intact, initially functioning system and are not treatment recommendations.

10 / UNDERSTAND & APPLY

Worked balances and causal tests

Original cases deliberately separate carbon, carrier and ATP statements.

ORIGINAL WORKED EXAMPLE

Gross versus net glycolysis

Three glucose molecules complete glycolysis. Find gross ATP, ATP invested, net ATP, pyruvate and NADH.

  1. Each glucose uses two ATP and makes four gross.
  2. Multiply all glycolytic outputs by three: investment six, gross twelve, six pyruvates and six NADH.
  3. Subtract investment from gross only once.

Answer 12 gross ATP, 6 invested, 6 net ATP, 6 pyruvate and 6 NADH.

ORIGINAL WORKED EXAMPLE

The pyruvate checkpoint

Two pyruvates are converted to acetyl-CoA before either acetyl group enters the cycle. What has been produced?

  1. Each three-carbon pyruvate loses one carbon as carbon dioxide.
  2. Each also reduces one NAD+ and supplies one two-carbon acetyl group.
  3. Cycle products are not yet included.

Answer 2 acetyl-CoA, 2 CO2 and 2 NADH; no direct ATP from the link reaction.

ORIGINAL WORKED EXAMPLE

One turn is not one glucose

A question reports six NADH, two FAD-linked reductions and two ATP equivalents from the cycle. How many turns occurred?

  1. Divide the NADH count by three per turn to obtain two turns.
  2. The other counts agree with one FAD-linked reduction and one ATP equivalent per turn.
  3. Two turns correspond to two acetyl groups, the usual supply from one glucose.

Answer Two turns, releasing four CO2 in the cycle.

ORIGINAL WORKED EXAMPLE

Carrier-entry comparison

Two electron pairs enter via complex I and two enter via complex II. Does each pair drive the same proton-pumping route?

  1. Both routes meet at ubiquinone and then use III and IV.
  2. Only the complex-I entry route includes pumping by complex I.
  3. Complex II does not compensate with its own proton pump.

Answer No. Complex-II entry bypasses one pumping step and has a lower illustrative ATP return.

ORIGINAL WORKED EXAMPLE

A declared ATP model

Use 2.5 ATP per NADH, 1.5 per FAD-linked pair and four direct ATP equivalents, assuming ten NADH have matrix-equivalent entry. Calculate the total.

  1. NADH contribution is 10 × 2.5 = 25.
  2. FAD-linked contribution is 2 × 1.5 = 3.
  3. Add four direct equivalents and retain the stated assumptions.

Answer 32 ATP equivalents under this model, not a universal cellular yield.

ORIGINAL WORKED EXAMPLE

Fermentation rescue

An oxygen-limited tissue still has glucose but its NAD+ pool is becoming reduced. What immediate role can alcoholic fermentation serve?

  1. The NAD+-dependent glycolytic oxidation would slow without carrier recycling.
  2. Reduction of acetaldehyde uses NADH and regenerates NAD+.
  3. Glycolysis can therefore continue supplying its small substrate-level ATP yield.

Answer Carrier regeneration, allowing net two ATP per fermented glucose through glycolysis; fermentation does not add a large oxidative yield.

ORIGINAL WORKED EXAMPLE

Uncoupling evidence

A preparation consumes oxygen but ATP production falls after membrane proton permeability increases. Is complete chain blockage the best explanation?

  1. Oxygen consumption shows electrons still reach the terminal acceptor.
  2. Increased proton leak reduces the retained proton-motive force.
  3. ATP synthase then has less driving force despite electron transfer.

Answer Uncoupling fits better than complete electron-chain blockade under the stated observations.

ORIGINAL WORKED EXAMPLE

An RQ measurement

A tissue releases 18 micromoles CO2 while consuming 24 micromoles O2 over the same interval. Calculate RQ and assess the inference.

  1. Use the same molar basis and interval.
  2. RQ = 18/24 = 0.75.
  3. A value below one is compatible with substantial oxidation of reduced substrates such as fats, but does not identify a unique mixture.

Answer RQ = 0.75; substrate identity is not uniquely established.

ORIGINAL WORKED EXAMPLE

Identify the ATP-producing step

A three-carbon intermediate is oxidised while NAD+ becomes NADH and free Pi is added. The resulting compound then transfers phosphate to ADP. Which event makes ATP?

  1. The first event is glyceraldehyde-3-phosphate oxidation and phosphorylation to 1,3-bisphosphoglycerate.
  2. The next event transfers phosphate from 1,3-bisphosphoglycerate to ADP, making ATP and 3-phosphoglycerate.
  3. A second substrate-level step occurs later when PEP becomes pyruvate.

Answer The phosphate-transfer event makes ATP; the preceding oxidation/Pi-addition event makes NADH, not ATP.

11 / UNDERSTAND & APPLY

Original solved practice

State the pathway stage before using a memorised yield.

ORIGINAL PRACTICE · 1

Does daylight net CO2 uptake prove that a leaf has stopped respiring?

Reveal answer & reasoning

No.

Photosynthetic uptake can exceed simultaneous respiratory release.

ORIGINAL PRACTICE · 2

How many carbon atoms are lost as CO2 during glycolysis of one glucose?

Reveal answer & reasoning

Zero.

The six carbons remain in two three-carbon pyruvates.

ORIGINAL PRACTICE · 3

What is the direct ATP gain from glycolysis if four are produced and two invested?

Reveal answer & reasoning

Two ATP net.

Gross and net are different accounts.

ORIGINAL PRACTICE · 4

Why can glycolysis stop without oxygen even though it does not directly use oxygen?

Reveal answer & reasoning

Failure to regenerate NAD+ can limit its oxidation step.

An indirect dependency is different from direct oxygen consumption.

ORIGINAL PRACTICE · 5

Name the inner-membrane-associated citric-cycle enzyme.

Reveal answer & reasoning

Succinate dehydrogenase.

It also functions as respiratory complex II.

ORIGINAL PRACTICE · 6

What does one cycle turn regenerate?

Reveal answer & reasoning

Oxaloacetate.

Regeneration permits another acetyl group to enter; it is not net consumption of the acceptor.

ORIGINAL PRACTICE · 7

What are cycle outputs for two acetyl-CoA, excluding the link reaction?

Reveal answer & reasoning

6 NADH, 2 FAD-linked reduction equivalents, 2 ATP/GTP equivalents and 4 CO2.

Double the per-turn ledger and do not add pyruvate oxidation again.

ORIGINAL PRACTICE · 8

Does free FADH2 normally diffuse from complex II to complex III?

Reveal answer & reasoning

No.

The enzyme-bound flavin transfers electrons through complex II to ubiquinone; textbook FADH2 counts are reducing-equivalent bookkeeping.

ORIGINAL PRACTICE · 9

Which standard complexes pump protons, and which carrier joins III to IV?

Reveal answer & reasoning

I, III and IV; cytochrome c joins III to IV.

Complex II is an entry route without proton pumping.

ORIGINAL PRACTICE · 10

Where do protons move through mitochondrial ATP synthase during synthesis?

Reveal answer & reasoning

From the intermembrane-space side into the matrix.

This return uses the gradient built by outward pumping.

ORIGINAL PRACTICE · 11

At complex IV, is oxygen the source of respiratory CO2?

Reveal answer & reasoning

No; it is reduced to water.

CO2 is released by decarboxylation of carbon-containing substrates.

ORIGINAL PRACTICE · 12

What is the net ATP of standard alcoholic fermentation of four glucose molecules?

Reveal answer & reasoning

Eight ATP.

Each glucose yields two net ATP through glycolysis, with fermentation recycling NAD+.

ORIGINAL PRACTICE · 13

Why is a calculated 38 ATP not directly comparable with a 32 ATP result without checking assumptions?

Reveal answer & reasoning

They may use different carrier-to-ATP conventions and transport assumptions.

Using older 3/2 and modern approximate 2.5/1.5 values in one sum is inconsistent.

ORIGINAL PRACTICE · 14

If both CO2 and O2 rates double at unchanged composition, what happens to RQ?

Reveal answer & reasoning

It stays the same.

The ratio has both numerator and denominator multiplied by two.

12 / UNDERSTAND & APPLY

Revision as four linked accounts

Trace glucose carbon through pyruvate, acetyl-CoA and carbon dioxide. In parallel, track oxidised versus reduced carriers, then locate proton pumping and return. Only then add direct and oxidative ATP using one explicit convention. A correct answer explains why a count or prediction follows; it does not merely repeat a pathway name.

KEEP THE BIG IDEAS

Quick revision

  • One glucose yields two pyruvates and two cycle turns after the link reaction.
  • Electron carriers are recycled and are not ATP molecules.
  • I, III and IV pump protons in the standard mitochondrial scheme; II does not.
  • Oxygen accepts electrons to form water, while carbon dioxide comes from decarboxylation.
  • ATP totals require stated coupling and transport assumptions.
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