Use repeat-number inheritance, fragment measurements and explicit statistical models to understand what a DNA profile can establish.
NEET UG34 min study guide12 indexed sections
BY THE END, YOU CAN
Explain repeat-number variation and diploid marker genotypes.
Distinguish historical VNTR probing from modern STR profiling.
Interpret clean profiles, fragment lengths and elementary genotype probabilities.
Identify limits involving mixtures, relatives, conditional probabilities and sample context.
BEFORE YOU START
DNA complementarity and chromosome inheritance
Mendelian segregation
Hardy–Weinberg genotype frequencies and probability products
Original educational lesson. Work through the examples before revealing the practice answers. Check the current official syllabus separately; historical question frequency does not establish eligibility or predict future questions.
CONNECT THE CONCEPT TO THE EXAM
Selected exam questions & worked solutions
These selected examples are separate from the original practice below. Each identifies its exam, year and wording. They do not represent every paper or every selected year.
No source-verified exam questions have been published for this lesson yet. The worked examples and practice below are original teaching material, not past-exam questions.
01 / UNDERSTAND & APPLY
1. Compare variable markers rather than reading an entire person
DNA fingerprinting, also called DNA profiling in modern usage, compares selected variable regions of DNA. A profile records features such as repeat-number alleles at several loci. It is not a photograph of chromosomes, a complete genome sequence or an image of the ridges on a finger.
Alec Jeffreys developed the original DNA-fingerprinting approach in 1984 through research on highly variable repeated DNA. Historical minisatellite band patterns and modern short tandem repeat profiles share the principle of comparing inherited variation, but their measurement methods and interpretation are not identical.
Most human DNA is shared among people. Profiling gains discriminating power by selecting loci with useful variation and combining information across them. One shared marker is unsurprising; a well-characterised multilocus profile can be much more informative. The strength of evidence must nevertheless be calculated within an appropriate model.
This lesson uses invented fragments, alleles and anonymous sample labels. Its purpose is to teach inheritance and evidence reasoning, not to identify an actual person, judge a legal case or draw conclusions about a real family. A matching profile does not by itself establish what someone did or when DNA reached a location.
02 / UNDERSTAND & APPLY
2. Repeat number creates measurable allele differences
A tandem repeat consists of a short sequence unit repeated beside itself. If one chromosome carries six copies and another ten copies at the same locus, the repeat region differs in length even if the repeat motif is the same. Variable number tandem repeat, or VNTR, is commonly used in school treatments for highly variable minisatellite regions. STRs have shorter repeat units and are widely used in modern profiling.
For a fictional repeat motif four base pairs long, an allele with eight copies contributes 32 bp of repeat DNA. Twelve copies contribute 48 bp. If the same measured flanking sequence is included in each fragment, the total fragment-length difference remains 16 bp. The flanks must not be counted as extra repeat units.
Polymorphism describes variation present in a population. Older teaching definitions often use a frequency threshold of about 1% to distinguish common polymorphisms from rarer variants. That convention is not a law stating that a DNA difference below the threshold cannot be inherited, detected or informative.
Repetitive DNA may occur in coding or noncoding contexts, but many identification markers are chosen outside protein-coding regions. Noncoding does not mean incapable of inheritance or automatically devoid of function. The word satellite historically relates to repetitive DNA fractions distinguished by physical properties; it does not mean a separate chromosome orbiting the nucleus.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
Fictional single-locus model with identical measured flanks and no other sequence-length variation. Each R box represents a four-base-pair motif. Flank widths are schematic and not drawn to the repeat-box base-pair scale.
03 / UNDERSTAND & APPLY
3. A diploid marker usually supplies two allele copies
At an ordinary autosomal STR locus, an individual normally carries one allele inherited through each parent. A genotype written 8,12 indicates repeat-number alleles eight and twelve; it does not mean twenty chromosomes or a single allele with twenty repeats. If both copies have eight repeats, the genotype is 8,8.
A heterozygote can yield two allele positions in a clean locus-specific length profile. A homozygote can yield one position because the same-length products coincide. One peak therefore does not imply that the person has only one chromosome or only one DNA molecule in the sample.
Across many autosomal loci, the pattern generally reflects Mendelian segregation. With a parent 8,12 and another 10,14, the possible child genotypes at that locus are 8,10; 8,14; 12,10; and 12,14 under the simple model. Each receives one allele from each parent.
These models assume correctly typed samples, ordinary diploid inheritance, no new mutation and no mixture or other complication. Real interpretation considers departures from those assumptions. A classroom mismatch under the model is an inference about that model, not an accusation or a definitive statement about a real relationship.
04 / UNDERSTAND & APPLY
4. Historical band patterns combined size separation with sequence recognition
In the classical VNTR approach, DNA fragments containing repeat regions were distinguished by length and detected with complementary probes. Conceptually, restriction cleavage produces fragments, electrophoresis separates them, denaturation makes strands available for hybridisation, and transfer to a membrane preserves their relative positions for probing.
A labelled probe binds a sufficiently complementary sequence. Detection then reveals selected fragments rather than every DNA fragment in the sample. Southern blotting concerns DNA; Northern blotting concerns RNA, and Western blotting detects proteins. Their names should not be exchanged merely because all can produce visible bands.
A multilocus probe can reveal many bands from different genomic locations, whereas a locus-specific interpretation concerns a defined marker. Counting every band in a historical multilocus picture as a separate allele at one diploid locus is therefore incorrect.
These are conceptual stages, not operating instructions. Probe choice, fragment integrity and specificity affect what is visible. A missing signal can reflect failure to detect material, so a diagram must state when it assumes complete, reliable detection.
05 / UNDERSTAND & APPLY
5. Fragment position is a measurement, not an identity verdict
DNA’s negatively charged backbone allows movement toward the positive electrode in an electric field. For comparable linear fragments in a suitable gel, smaller fragments usually travel farther than larger ones. A size standard is needed to relate positions to fragment lengths; the distance is not generally a simple linear ruler of base-pair number.
Modern STR profiling commonly targets defined regions with amplification and records the resulting allele positions instrumentally. A profile may be shown as peaks rather than dark bands. The position indicates an allele’s measured size or assignment; peak height is not a repeat count.
A fragment length includes the repeat region and any measured flanking sequence. If two loci have different flanks, identical total lengths do not necessarily mean identical repeat numbers. Locus identity and calibration are therefore essential parts of the result.
Sequence-based profiling can sometimes distinguish alleles that have the same overall length but different internal sequence. More detailed information also requires appropriate reference data and validation. There is no universal fixed number of loci that describes every historical method, jurisdiction and current platform.
06 / UNDERSTAND & APPLY
6. Compare corresponding loci and preserve the distinction between exclusion and support
In an idealised complete single-source profile, sample A has locus L1 genotype 8,12 and locus L2 genotype 10,11. Sample B has the same pair at each locus. They are concordant for the markers examined. Sample C has 8,13 at L1, so it differs at that marker even if L2 matches.
Alleles must be compared within the same locus. An allele labelled 12 at L1 does not compensate for a missing 12 at L2. Likewise, genotype 8,12 equals 12,8 because the order of the two unphased allele labels is not meaningful.
Under the stated clean single-source model, a reliable incompatible allele can exclude a proposed common source. A concordant profile supports compatibility but does not logically prove that no other individual could share it. Identical twins usually share the standard inherited STR profile, and relatives are more likely to share alleles than unrelated people.
An incomplete profile contains less information than a complete one. One should report the markers actually observed rather than silently filling gaps from a comparison sample. Additional data can strengthen or weaken an interpretation; uncertainty is part of the evidence, not a reason to replace it with certainty.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
Invented complete single-source profiles with no mutation, dropout or artefacts. Allele numbers represent repeat counts at their own locus, not absolute lengths across different loci. Band positions show ordinal size separation rather than a calibrated migration law. These are educational samples, not real casework.
07 / UNDERSTAND & APPLY
7. Rarity depends on genotype frequencies and model assumptions
For an elementary autosomal locus in Hardy–Weinberg equilibrium, an allele with frequency p has homozygote frequency p². Two different alleles with frequencies p and q have heterozygote frequency 2pq, because the two parental transmission orders lead to the same unordered genotype.
If allele 8 has frequency 0.20 and allele 12 frequency 0.10, the idealised frequency of genotype 8,12 is 2 × 0.20 × 0.10 = 0.04. The frequency of 8,8 is 0.20² = 0.04 in this particular example. Equal numerical results do not mean the formulas are interchangeable.
For suitable independent loci, genotype frequencies can be multiplied to estimate a multilocus profile frequency. If three fictional locus-genotype frequencies are 0.04, 0.05 and 0.02, their product is 0.00004, or one in 25,000. The product rule requires the stated independence assumptions and appropriate population information.
Real forensic calculations can account for population structure, relatedness, sample uncertainty and other factors beyond this elementary model. A school exercise should supply its assumptions. It is invalid to invent allele frequencies, multiply linked markers as independent without justification, or apply an unrelated-person model to a specified close relative.
08 / UNDERSTAND & APPLY
8. A random-match probability is not the probability of guilt
A random-match probability concerns how often an unrelated randomly selected individual from the stated population model would have the specified profile. It does not directly equal the probability that a particular person is the source, and it certainly does not equal the probability of innocence or guilt.
Likelihood ratios compare how probable the observed evidence is under two explicitly stated propositions. For a fictional evidence event E, if P(E | H1) = 0.80 and P(E | H2) = 0.02, the likelihood ratio is 40. This says the evidence is forty times as probable under H1 as under H2 in that model.
It does not say that H1 has probability 40 or 97.5%. A posterior probability would additionally require prior odds and a defensible model connecting all the evidence. Swapping P(E | H) with P(H | E) reverses the conditional question.
Even a strong source-level result does not determine the activity that deposited DNA. The same biological material can be consistent with different timing or transfer circumstances. A responsible answer separates the measured marker pattern, the strength of source evidence and any broader conclusion about events.
09 / UNDERSTAND & APPLY
9. Mixed and low-level samples require additional uncertainty models
A sample can contain DNA from more than one contributor. Several individuals can share alleles, and their combined signals overlap. Therefore, finding all of one candidate profile’s alleles somewhere in a mixture does not establish that the candidate contributed: other contributors can jointly supply the same set.
Low-level or degraded material may yield incomplete detection. Allele dropout means a real allele is not observed; additional signals may arise from contamination or analytical artefacts. Stutter products associated with repeat amplification can complicate peak interpretation. A small peak is not automatically a true additional contributor allele.
For a fictional mixture with observed alleles 8,10,12,14 at one locus, possible pairings include contributors 8,10 plus 12,14, or 8,12 plus 10,14. The allele list alone does not distinguish these decompositions. More loci and an appropriate model are needed.
Mixture interpretation uses validated biological and statistical assumptions rather than merely counting coloured peaks. This lesson’s clean-profile puzzles must not be transferred unchanged to complex mixtures. If the conditions required for a simple inference are absent, the correct response is to state that limitation.
Full-size scientific diagram. Swipe or scroll horizontally; keyboard users can focus the diagram and use arrow keys.
Fictional two-person diploid example with full detection and no shared alleles, mutation or artefacts. It isolates pairing ambiguity; real mixtures can have additional complications and require validated quantitative models. No real contributor identity is inferred.
10 / UNDERSTAND & APPLY
10. A result is only as useful as its sample context and interpretation
A profile must remain linked to the correct sample identity and handling record. Contamination, sample switching or poor-quality material can change the evidential meaning even when the underlying genetic principles are sound. Controls and traceable documentation address different failure modes from mathematical match calculations.
The usual nuclear DNA profile is broadly shared across a person’s nucleated tissues, but sample biology still matters. Mature human red blood cells lack nuclei, so nuclear DNA recovered from blood commonly comes from other cellular components such as white blood cells. Hair material with and without root-associated tissue can differ in the nuclear DNA available.
DNA profiling has uses in identification, biological relationship studies, conservation and other research. Each application requires consent or other appropriate authority, suitable reference material and careful interpretation. Genetic data can reveal information about relatives as well as the sampled individual.
Privacy and fairness require more than removing names from a data table. Access, retention, secondary uses and the possibility of re-identification all matter. This is a scientific discussion of evidence and responsibility, not legal advice or instructions for covert sample collection.
11 / UNDERSTAND & APPLY
11. Eight original worked reasoning cases
All samples, loci and frequencies are invented educational examples, not casework.
ORIGINAL WORKED EXAMPLE
Count repeat DNA
An invented STR has a 4 bp motif, ten repeats and 80 bp of measured flanks. Find total fragment length.
Repeat DNA contributes 4 × 10 = 40 bp.
Add the stated flanks once.
Do not divide the entire fragment length by four to infer repeats.
Answer 120 bp.
ORIGINAL WORKED EXAMPLE
Infer repeat difference
Two alleles at the same invented locus are 144 and 160 bp with identical flanks and a 4 bp motif. How many repeat units differ?
The fragment difference is 160 − 144 = 16 bp.
Identical flanks cancel from the difference.
16/4 = 4.
Answer Four repeat units.
ORIGINAL WORKED EXAMPLE
A one-position profile
A clean diploid autosomal locus shows one calibrated allele position, 9. Under the complete-detection model, what genotype is consistent?
Two same-length alleles overlap in the readout.
One position need not mean one allele copy.
The stated complete-detection assumption rules out an undetected second length in this model.
Answer 9,9, not a one-chromosome conclusion.
ORIGINAL WORKED EXAMPLE
Track fictional inheritance
One parent is 8,12 and the other 10,14. List the four equally likely marker genotypes in the simple model.
Gametes from the first carry 8 or 12.
Gametes from the second carry 10 or 14.
Combine one allele from each route.
Answer 8,10; 8,14; 12,10; 12,14, each with probability 1/4.
ORIGINAL WORKED EXAMPLE
Compare the correct locus
Sample A: L1 8,12; L2 10,11. Sample B: L1 12,8; L2 10,11. Sample C: L1 8,13; L2 10,11. Which is concordant with A at both loci?
Order within the unphased pair does not matter.
B has the same two alleles at each corresponding locus.
C differs at L1 despite matching L2.
Answer B is concordant; C differs under the clean single-source model.
ORIGINAL WORKED EXAMPLE
Calculate a profile frequency
Assume three independent locus-genotype frequencies 0.04, 0.05 and 0.02. Find the product.
0.04 × 0.05 = 0.002.
0.002 × 0.02 = 0.00004.
The reciprocal is 25,000.
Answer 0.00004, or one in 25,000 under the stated population model.
ORIGINAL WORKED EXAMPLE
Read a likelihood ratio
Fictional evidence has probabilities 0.80 under H1 and 0.02 under H2. Interpret their ratio.
Divide the evidence probabilities in the stated order.
0.80/0.02 = 40.
The result compares evidence likelihoods, not posterior probabilities of the propositions.
Answer The evidence is 40 times as probable under H1 as under H2 in this model.
ORIGINAL WORKED EXAMPLE
Show mixture ambiguity
Observed alleles are 8,10,12,14 at one locus. Must one contributor be 8,12?
The pair 8,12 could combine with 10,14.
But 8,10 combined with 12,14 gives the same allele set.
The single-locus list does not choose one pairing.
Answer No. More than one contributor combination is compatible.
12 / UNDERSTAND & APPLY
12. Original practice with explained answers
Keep locus identity, detection assumptions and conditional probabilities explicit.
ORIGINAL PRACTICE · 1
Does a standard STR profile sequence every base of a human genome?
Reveal answer & reasoning
No.
It examines selected markers rather than the entire genome.
ORIGINAL PRACTICE · 2
Who developed the original DNA-fingerprinting approach in 1984?
Reveal answer & reasoning
Alec Jeffreys.
The historical work used highly variable repeated DNA.
ORIGINAL PRACTICE · 3
An allele has seven copies of a 5 bp motif. How much repeat DNA is present?
Reveal answer & reasoning
35 bp.
7 × 5 = 35; any flanking DNA is additional.
ORIGINAL PRACTICE · 4
With 60 bp of flanks and eight copies of a 4 bp motif, what is the fragment length?
Reveal answer & reasoning
92 bp.
60 + 8 × 4 = 92.
ORIGINAL PRACTICE · 5
Does genotype 8,12 mean one allele with twenty repeats?
Reveal answer & reasoning
No.
It records two allele copies at one diploid locus.
ORIGINAL PRACTICE · 6
Why can a homozygote produce one allele peak?
Reveal answer & reasoning
The two same-length products coincide.
Peak count is not chromosome-copy count.
ORIGINAL PRACTICE · 7
What does a Southern blot detect?
Reveal answer & reasoning
Selected DNA sequences through probe hybridisation.
Northern concerns RNA; Western concerns proteins.
ORIGINAL PRACTICE · 8
For comparable linear DNA fragments, which usually travels farther in a suitable gel: 100 bp or 300 bp?
Reveal answer & reasoning
100 bp.
Smaller fragments generally pass through the matrix more readily.
ORIGINAL PRACTICE · 9
Does peak height directly state STR repeat number?
Reveal answer & reasoning
No.
Allele assignment relates to calibrated position or sequence, while height concerns signal.
ORIGINAL PRACTICE · 10
Are 8,12 and 12,8 different unphased genotypes?
Reveal answer & reasoning
No.
The unordered allele pair is the same.
ORIGINAL PRACTICE · 11
With p = 0.30, what is the elementary Hardy–Weinberg homozygote frequency?
Reveal answer & reasoning
0.09.
p² = 0.30² = 0.09.
ORIGINAL PRACTICE · 12
With p = 0.30 and q = 0.20 for distinct alleles, what is the elementary heterozygote frequency?
Reveal answer & reasoning
0.12.
2pq = 2 × 0.30 × 0.20 = 0.12.
ORIGINAL PRACTICE · 13
Can linked locus frequencies always be multiplied as independent?
Reveal answer & reasoning
No.
The product rule needs justified independence or a suitable dependence model.
ORIGINAL PRACTICE · 14
Does one-in-25,000 profile frequency mean a particular person has a one-in-25,000 probability of innocence?
Reveal answer & reasoning
No.
That reverses and changes the probability question.
ORIGINAL PRACTICE · 15
Does seeing all of a candidate’s alleles in a mixture establish contribution?
Reveal answer & reasoning
No.
Other contributors can jointly supply the same allele set.
ORIGINAL PRACTICE · 16
Do mature human red blood cells provide ordinary nuclear DNA?
Reveal answer & reasoning
No.
They lack nuclei; blood nuclear DNA commonly comes from white blood cells and other nucleated material.
KEEP THE BIG IDEAS
Quick revision
A DNA profile compares selected variable loci rather than the whole genome.
One peak can represent two same-length allele copies.
Compare alleles at corresponding loci, not anywhere in a profile.
A random-match probability is not a probability of guilt or innocence.
Mixtures and incomplete detection require models beyond clean single-source puzzles.
The teaching notes, worked explanations and original practice are written for this lesson. Separately labeled selected exam questions identify their exam, year, source and whether wording is paraphrased or an exact excerpt. Educational references do not certify current exam coverage.
NCERT Biology, Class XII: Molecular Basis of Inheritance (textbook reference)